Answer:
economic profit = $11225
Explanation:
given data
sells = 975 units
cost = $30 per unit
cost of producing goods = $15
implicit costs = $3,400
solution
total revenue = 975 × 30 = $29250
and total cost = 975 × 15 = $14625
so here Total profit will be as
Total profit = $29250 - $14625 = $14625
so here economic profit will be
economic profit = Total profit - implicit costs
economic profit = $14625 - $3,400
economic profit = $11225
Answer:
Hilary is a retired teacher who lives in Miami and does some consulting work for extra cash. At a wage of $50 per hour, she is willing to work 10 hours per week. At $65 per hour, she is willing to work 19 hours per week.
Using the midpoint method, the elasticity of Hilary’s labor supply between the wages of $50 and $65 per hour is approximately 2.37 , which means that Hilary’s supply of labor over this wage range is elastic.
Explanation:
Midpoint elasticity = (Change in labor supplied / Average labor supplied) / (Change in wage rate / Average wage rate)
= [(19 - 10) / (19 + 10) / 2] / [$(65 - 50) / $(65 + 50) / 2]
= [9 / (29 / 2)] / [15 / (115 / 2)]
= (9 / 14.5) / (15 / 57.5)
= 0.62/0.26
Midpoint elasticity = 2.37
Once elasticity is greater than 1, supply of labor is Elastic.
Answer:
Hyoid bone
Explanation:
The hyoid is anchored by muscles from the anterior, posterior and inferior directions, and aids in tongue movement and swallowing.
Answer:
Dealer "B" at $5,595.00
Explanation:
Comparison of cost charges for dealer A and dealer B will have to include the one-year maintenance offered by dealer B.
The cost for dealer A will be
maintenance for one year= $75 x 12= $900
cost of the car= $4,995.00.
total cost for dealer A
= $4,995.00 + $900
=$5,895
The cost from dealer B is $5,595.
Dealer B has the better deal as they are cheaper by $300
( $5,895- $5,595)
Answer:
Explanation is given below
Explanation:
Given that, the total budget for the media is only $1,000 per month.
For the allocation, each type of media would get at least 25% of the budget.
Hence, from the available information, we have the following:
Parameters:
$1000 = Monthly advertising budget
25%= Minimum spending for each type of media
50 = Value of the index for local newspaper advertising
80= Value of the index for spot radio advertising
Decision variables;
x1= Newspaper advertising budget
x2= Radio advertising budget
LP Model;
Maximize Z=50x1+ 80x2
Subject to:x1+ x2≤1000
x1≥ 250
x2≥ 250
x1,x2≥ 0
p.s. OptimumZ=72, 500,
x1=250,
x2=750