Answer:
A transition down six units
Step-by-step explanation:
-2-6=-8
Answer:
Step-by-step explanation:
So first thing is that slope intercept form is setup like this
y=mx+b
m=slope
b=y intercept
the slope is change in y over change in x
as y goes down 2 x goes up 5
so the slope is -2/5
the y intercept is at (0,-1) so the y intercept is -1
therefore the answer is
have a great day :)
Answer:
Step-by-step explanation:
P(y) = y³ + 2y² + 2y + 1
P(-1) = (-1)³ + 2*(-1)² + 2*(-1) + 1
= -1 + 2 - 2 + 1
= 0
As, P(-1) = 0, (y + 1) is a factor.
Use synthetic division or remainder theorem.
-1 1 2 2 1
<u> 0 -1 -1 -1 </u>
1 1 1 0
quotient = y² + y + 1
y³ + 2y² + 2y + 1 = ( y + 1) (y² + y + 1)
So to fine slope you would use the formula down below:
rise/run
So use a graphed point, 0, -5 and you rise or count up quadrants up to a point and then horizontally move to when you find that point.
So from 0,-5 go up 9 vertically, and you would be on the 4
Go horizontal 3 spots and your on a designated point.
So the rise is four and the run is 3
So 4/3 is the slope
In the y= Mx + b equation you would set the equation like this:
y= 4/3 + -5
The m in this formula stands for the slop and the b stands for the y-intercept
The y-intercept is the point that is on the y-axis and where it starts.
Step-by-step explanation:
The value of sin(2x) is \sin(2x) = - \frac{\sqrt{15}}{8}sin(2x)=−
8
15
How to determine the value of sin(2x)
The cosine ratio is given as:
\cos(x) = -\frac 14cos(x)=−
4
1
Calculate sine(x) using the following identity equation
\sin^2(x) + \cos^2(x) = 1sin
2
(x)+cos
2
(x)=1
So we have:
\sin^2(x) + (1/4)^2 = 1sin
2
(x)+(1/4)
2
=1
\sin^2(x) + 1/16= 1sin
2
(x)+1/16=1
Subtract 1/16 from both sides
\sin^2(x) = 15/16sin
2
(x)=15/16
Take the square root of both sides
\sin(x) = \pm \sqrt{15/16
Given that
tan(x) < 0
It means that:
sin(x) < 0
So, we have:
\sin(x) = -\sqrt{15/16
Simplify
\sin(x) = \sqrt{15}/4sin(x)=
15
/4
sin(2x) is then calculated as:
\sin(2x) = 2\sin(x)\cos(x)sin(2x)=2sin(x)cos(x)
So, we have:
\sin(2x) = -2 * \frac{\sqrt{15}}{4} * \frac 14sin(2x)=−2∗
4
15
∗
4
1
This gives
\sin(2x) = - \frac{\sqrt{15}}{8}sin(2x)=−
8
15
