Solubility,,,,,add water to the mixture,salt will dissolve to form a solution while sand is insoluble,,,,,decant the salt solution as filtrate and remain with sand as residue,,,,,if salt crystals are needed,,,,evaporate the filtrate to dryness.
Answer: Aluminum, because it allows heat to flow easily.
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Answer: Option (3) is the correct answer.
Explanation:
When a more reactive element or atom replaces a less reactive atom then this type of reaction is known as single displacement reaction.
In the given reaction, potassium iodide reacts with fluorine and results in the formation of potassium fluoride and iodine.
Here, fluorine being more reactive displaces iodine from potassium iodide.
Therefore, it is a single replacement or displacement reaction.
Answer:
ΔrxnH = -580.5 kJ
Explanation:
To solve this question we are going to help ourselves with Hess´s law.
Basically the strategy here is to work in an algebraic way with the three first reactions so as to reprduce the desired equation when we add them together, paying particular attention to place the reactants and products in the order that they are in the desired equation.
Notice that in the 3rd reaction we have 2 mol Na₂O (s) which is a reactant but with a coefficient of one, so we will multiply this equation by 1/2-
The 2nd equation has Na₂SO₄ as a reactant and it is a product in our required equation, therefore we will reverse the 2nd . Note the coefficient is 1 so we do not need to multiply.
This leads to the first equation and since we need to cancel 2 NaOH, we will nedd to multiply by 2 the first one.
Taking 1/2 eq 3 + (-) eq 2 + 2 eq 1 should do it.
Na₂O (s) + H₂ (g) ⇒ 2 Na (s) + H₂O(l) ΔrxnHº = 259 / 2 kJ 1/2 eq3
+ 2NaOH(s) + SO₃(g) ⇒ Na₂SO₄ (s) + H₂O (l) ΔrxnHº = -418 kJ - eq 2
+ 2Na (s) + 2 H₂O (l) ⇒ 2 NaOH (s) + H₂ (g) ΔrxnHº = -146 x 2 2 eq 1
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Na₂O (s) + SO₃ (g) ⇒ Na₂SO₄ (s) ΔrxnHº = 259/2 + (-418) + (-146) x 2 kJ
ΔrxnH = -580.5 kJ
Given parameters:
Mass of rock = 14g
Volume of rock = 12cm³
Unknown:
Density of the rock = ?
Density of a substance is the amount of substance it contains per unit volume. Mathematically, this can be expressed as;
Density =
Now simply input the parameters and solve;
Density = = 1.17g/cm³
Density of the rock that Jack has is 1.17g/cm³