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3 years ago

Given the reaction agi(s) ↔ ag+(aq) + i-(aq) solution equilibrium is reached in the system when

1 answer:

7 0

Missing question:
1) the rate of dissolving reaches zero
2) the rate of crystallization reaches zero 
3) the rate of dissolving is zero and the rate of crystallization is greater than zero.
4) both the rate of dissolving and the rate of crystallization are equal and greater than zero.

Answer is: 4) both the rate of dissolving and the rate of crystallization are equal and greater than zero.
Silver chloride (AgCl) dissolves and form silver and chlorine ions, in the same time silver and chlorine ions crystallizate and form solid salt silver chloride.
In equilibrium rates of dissolvinf and crysallization and concentration of ions do not change.

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Calculate the solubility of ( = ) in moles per liter. Ignore any acid–base properties. s = mol/L Calculate the solubility of ( =

BaLLatris [955]

This is an incomplete question, here is a complete question.

Calculate the solubility of each of the following compounds in moles per liter. Ignore any acid-base properties.

CaCO₃, Ksp = 8.7 × 10⁻⁹

Answer : The solubility of CaCO₃ is, $9.33\times 10^{-5}mol/L$

Explanation :

As we know that CaCO₃ dissociates to give $Ca^{2+}$ ion and $CO_3^{2-}$ ion.

The solubility equilibrium reaction will be:

$CaCO_3\rightleftharpoons Ca^{2+}+CO_3^{2-}$

The expression for solubility constant for this reaction will be,

$K_{sp}=[Ca^{2+}][CO_3^{2-}]$

Let solubility of CaCO₃ be, 's'

$K_{sp}=(s)\times (s)$

$K_{sp}=s^2$

$8.7\times 10^{-9}=s^2$

$s=9.33\times 10^{-5}mol/L$

Therefore, the solubility of CaCO₃ is, $9.33\times 10^{-5}mol/L$

4 0

3 years ago

Draw a lewis structure for hnc and assign the non-zero formal charges to each atom. draw the lewis structures with the formal ch

Yuliya22 [10]

Answer: H-C-N H-N-C C-H-N Notice that C-H-N is the same as N-H-C just written backwards. ( i.e. they have the same connectivtiy.) You can exclude the last one with H in the middle since H has two bonds and 4 electrons around it. At this point you couldn't differentiate between the first two, so I would give you the connectivity in such a problem, which in this case is H-C-N.

3 0

3 years ago

To objects (A and B) of the same temperature are in contact with each other? Which statement is true.

denpristay [2]

Que pa’so thosui? Esta bious classa?

5 0

3 years ago

Read 2 more answers

What is the volume of an irregular object if the initial volume in the graduated cylinder is 3.50 ml and it rises to 7.50 ml aft

Margarita [4]

Answer is: the volume of an irregular object is 4,00 ml.
Volume is the amount of space the object occupies and can be finded immersing it in water in a container with volume markings and than see how much the level of the container changes (goes up).
V(irregular object) = V(final volume) - V(initial volume).
V(irregular object) = 7,50 ml - 3,50 ml.
V(irregular object) = 4,00 ml.

8 0

3 years ago

A balloon is filled with 2.00 L of helium gas at sea level, 1.00 atm and 12.0ºC. The balloon is released and it rises to an alti

pshichka [43]

Answer:

THE VOLUME OF THE BALLOON IS 1.45 L

Explanation:

At sea level:

Volume = 2 L

Pressure = 1 atm

Temperature = 12 °C

At 30000 ft altitude:

Pressure = 0.30 atm

Temperature = -55°C

Volume = unknown

Using the general gas formula:

P1 V1 / T1 = P2 V2 / T2

Re-arranging the formula by making V2 the subject of the equation, we have;

V2 = P1 V1 T2 / T1 P2

V2 = 1 * 2 * 12 / 0.30 * 55

V2 = 24 / 16.5

V2 = 1.45 L

The volume of the balloon at the temperature of -55 C and 0.30 atm is 1.45 L

3 0

2 years ago