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3 years ago

The product of two numbers is 60. If half of their sum is 16, what are the two numbers? Help!!!!!!!!!

Mathematics

2 answers:

zysi [14]3 years ago

7 0

Answer:

The two numbers are 30 and 2.

Step-by-step explanation:

Write an equation:

If half of their sum is 16, then their sum is 32.

If the product of the two numbers are 60 then the following numbers might be it:

1, 2, 3, 4, 5, 6 10, 12, 15, 20, 30, 60

Then find a match that have a sum of 32.

The numbers 30 and 2 have a sum of 32 and that is it.

<h3><u><em>Please rate this and please give brainliest. Thanks!!! </em></u></h3><h3><u><em>Appreciate it! : ) </em></u></h3><h3><u><em>And always, </em></u></h3><h3><u><em>SIMPLIFY BANANAS : )</em></u></h3>

QveST [7]3 years ago

4 0

Answer:

The 2 other numbers: 22 and 22.

Step-by-step explanation:

60 - 16 = 44

44 ÷ 2 = 22

Then..... 22 + 22+ 16 = 60

Or...... 44 + 16 = 60

Hope this helps!!!

Please mark Brainliest!

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Consider the vector add = a + b = [13 12 11 10 10] and sub = a - b = [-11 - 6 - 14 8]. Find the vector a and b.

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a = [1 3 5 7 9] and b = [12 9 6 3 1]

Step-by-step explanation:

The addition of two vectors a and b is defined as

a + b = [13 12 11 10 10] .... (1)

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After adding (1) and (2), we get

(a + b) + (a - b)= [13 12 11 10 10] + [-11 - 6 - 1 4 8]

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Substitute the value of vector a in equation (1).

[1 3 5 7 9] + b = [13 12 11 10 10]

Subtract vector a from both sides.

b = [13 12 11 10 10] - [1 3 5 7 9]

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Answer:

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Step-by-step explanation:

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And

So, The measure of length CA = c = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

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