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pogonyaev
3 years ago
10

The product of two numbers is 60. If half of their sum is 16, what are the two numbers? Help!!!!!!!!!

Mathematics
2 answers:
zysi [14]3 years ago
7 0

Answer:

The two numbers are 30 and 2.

Step-by-step explanation:

Write an equation:

If half of their sum is 16, then their sum is 32.

If the product of the two numbers are 60 then the following numbers might be it:

1, 2, 3, 4, 5, 6         10, 12, 15, 20, 30, 60

Then find a match that have a sum of 32.

The numbers 30 and 2 have a sum of 32 and that is it.

<h3><u><em>Please rate this and please give brainliest. Thanks!!! </em></u></h3><h3><u><em>Appreciate it! : ) </em></u></h3><h3><u><em>And always, </em></u></h3><h3><u><em>SIMPLIFY BANANAS          : )</em></u></h3>

QveST [7]3 years ago
4 0

Answer:

The 2 other numbers: 22 and 22.

Step-by-step explanation:

60 - 16 = 44

44 ÷ 2 = 22

Then..... 22 + 22+ 16 = 60

Or...... 44 + 16 = 60

Hope this helps!!!

Please mark Brainliest!

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Katyanochek1 [597]
<h2>Answer:</h2>

\boxed{R_{4}=20\Omega}

<h2>Step-by-step explanation:</h2>

If resistors are in series, so the current  I is the same in all of them. In this problem we have four resistors. So, we can get a relationship between the Equivalent resistance  of series combination and the four resistors as follows:

R_{eq}=R_{1}+R_{2}+R_{3}+R_{4}

R_{eq} is the total resistance 50\Omega. Moreover:

R_{1}=5\Omega \\ R_{2}=10\Omega \\ R_{3}=15\Omega

Therefore:

50=5+10+15+R_{4} \\ \\ R_{4}=50-(5+10+15) \\ \\ R_{4}=50-30 \\ \\ \boxed{R_{4}=20\Omega}

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3 years ago
Y'all please answer this, i asked this two times already :(
Andrew [12]

Answer:

-7 C

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5 0
3 years ago
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Answer:

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