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PilotLPTM [1.2K]
4 years ago
11

Plzzz help me answer this question!!,!

Chemistry
1 answer:
omeli [17]4 years ago
7 0
I can’t see the picture for some reason
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Are elecronegativity values higher for metals than nonmetals.
Leya [2.2K]

Non-metals, which are organized on the right side of the periodic table, have higher electronegativity values than the metals.

Hope this helped!

3 0
3 years ago
From the balanced reaction:
Lelu [443]

Answer:

The mass of O₂ that will be needed to burn 36.1 g B₂H₆ is 125.29 g.

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3 years ago
I need an answer now please asap and you will me marked brainiest please it's missing I need it now.
BaLLatris [955]
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8 0
2 years ago
How many moles of aluminum oxide will be produced from 0.50 mol of oxygen? 4 al + 3 o2 2 al2o3?
LuckyWell [14K]
From the equation;
 4 Al + 3 O2 = 2 Al2O3
The mole ratio of Oxygen is to Aluminium hydroxide is  3:2.
Therefore; moles of Al2O3 is 
 (0.5/3 )× 2 = 0.333 moles
Therefore; The moles of aluminium oxide will be 0.333 moles
5 0
3 years ago
Read 2 more answers
One sphere has a radions of 181 cm, another has a radius of 5.01 cm. What is the difference in volume (in cubic centimeters) bet
PSYCHO15rus [73]

Answer:

2.4*10^{7}cm^{3}

Explanation:

First you should calculate the volume of a big sphere,so:

V_{big}=\frac{4}{3}\pi r^{3}

V_{big}=\frac{4}{3}\pi (181cm)^{3}

V_{big}=2.4*10^{7}cm^{3}

Then you calculate the volume of a small spehre, so:

V_{small}=\frac{4}{3}\pi r^{3}

V_{small}=\frac{4}{3}\pi (5.01cm)^{3}

V_{small}=5.3*10^{2}cm^{3}

Finally you subtract the two quantities:

V_{big}-V_{small}=2.4*10^{7}cm^{3}-5.3*10^{2}cm^{3}

V_{big}-V_{small}=2.4*10^{7}cm^{3}

5 0
3 years ago
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