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Nimfa-mama [501]
3 years ago
6

How many particles are in 1 mol of carbon? 1 mol of lithium? 1 mol of eggs? will 1 mol of each of these substances have the same

mass?
Chemistry
1 answer:
andrezito [222]3 years ago
8 0
<span>One mole of a substance contains Avogadro's number of atoms/molecules/the like. This would mean that all of the items described would have approximately 6.022 * 10^23 atoms, even though their masses would differ. This would be due to the molar mass of each substance being different because of the constituent elements in the substance.</span>
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Draw the mechanism for the williamson ether reaction using m-cresol and benzyl bromide (use sodium methoxide as the base).
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Below is the reaction of ether formation.

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Advanced flow measuring devices ? <br> I need info about this topic please
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Consider the equation below. CaCO3(s) &lt;—&gt;CaO(s) + CO2(g) what is the equilibrium constant expression for the given reactio
hichkok12 [17]

Answer:

Answer is: Keq = [CO₂].

Explanation:

Balanced chemical reaction: CaCO3(s) ⇄ CaO(s) + CO₂(g).

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Pure liquids (shown in chemical reactions by appending (l) to the chemical formula) and solids (shown in chemical equations by appending (s) to the chemical formula) not go in to he equilibrium constant expression, only gas state (shown in chemical reactions by appending (g) to the chemical formula) reactants and products go in to  the equilibrium constant expression

8 0
3 years ago
Read 2 more answers
What is the molarity of a solution prepared by dissolving.
ser-zykov [4K]

Answer:

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6 0
2 years ago
How many grams of sodium chromate, Na2CrO4, are needed to react completely with
JulsSmile [24]

Answer:

We need 27.0 grams of Na2CrO4 to react with 56.7 grams of AgNO3

Explanation:

Step 1: data given

Mass of silver nitrate AgNO3 = 56.7 grams

Molar mass AgNO3 = 169.87 g/mol

Molar mass of Na2CrO4 = 161.97 g/mol

Step 2: The balanced equation

2AgNO3 + Na2CrO4 → Ag2CrO4 + 2NaNO3

Step 3: Calculate moles AgNO3

Moles AgNO3 = mass AgNO3 / molar mass AgNO3

Moles AgNO3 = 56.7 grams / 169.87 g/mol

Moles AgNO3 = 0.334 moles

Step 4: Calculate moles Na2CrO4 moles needed

For 2 moles AgNO3 we need 1 mol Na2CrO4 to produce 1 mol Ag2CrO4 and 2 moles NaNO3

For 0.334 moles AgNO3 we need 0.334 / 2 = 0.167 moles Na2CrO4

Step 5: Calculate mass Na2CrO4

Mass Na2CrO4 = 0.167 moles * 161.97 g/mol

Mass Na2CrO4 = 27.0 grams

We need 27.0 grams of Na2CrO4 to react with 56.7 grams of AgNO3

8 0
3 years ago
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