Which is the best way to turn helium gas into liquid helium?

A 35 gram of saturated solution is distilled out completely. If the solubility of the solute is 110, find the amount of residue

kipiarov [429]

Answer:

3850g

Explanation:

Solubility is the amount of solute dissolved in a solvent.

Solubility is mass of solute÷mass of solvent

The solvent is 35grams

Solute?

Solubility of solute is 110

110=x/35

= 110 × 35

The amount of residue solute is 3850g

8 0

3 years ago

A student needs to standardize a base solution by titration with an acid solution of known concentration. She finds the volume o

kondor19780726 [428]

The steps usually involves adding the known solution (the titrant) to a known quantity of the unknown solution (the analyte) until the reaction is complete which can be understood in detail as below with the help of through out process of titration.

<h3 /><h3>What is Titration ?</h3>

A titration is a technique used to work out the concentration of an unknown solution based on its chemical reaction with a solution of known concentration.

Steps in order to determine the concenteration of base solution ;

(Acid-Base Titration)

Choose the titrant.
Choose the titrate.
Select the normality of the titrate.
Choose the volume of the liquid to be pipetted out.
Select the indicator.
Start titration.
End point is noted at the colour change of the solution.

From the final reading the normality of titrant can be calculated by the equation:

N₁V₁=N₂V₂

After finding the normality, the amount of given substance in the whole of the given solution can be calculated by the equation:

Mass = Equivalent weight x Normality \ Volume {1000}

Learn more about titration here ;

brainly.com/question/15365870

#SPJ1

6 0

3 years ago

The zero order reaction 2N2O→2N2+O2 has the reaction constant k is 6.28×10−3 molL s. If the initial concentration of N2O is 0.96

Talja [164]

<u>Answer:</u> The concentration of $N_2O$ in three significant figures will be 0.899 mol/L.

<u>Explanation:</u>

For the given reaction:

$2N_2O\rightarrow 2N_2+O_2$

The above reaction follows zero order kinetics. The rate law equation for zero order follows:

$k=\frac{1}{t}([A_o]-[A])$

where,

k = rate constant for the reaction = $6.28\times 10^{-3}\text{ mol }L^{-1}s^{-1}$

t = time taken = 10 sec

$[A_o]$ = initial concentration of the reactant = 0.962 mol/L

[A] = concentration of reactant after some time = ?

Putting values in above equation, we get:

$6.28\times 10^{-3}=\frac{1}{10}(0.962-[A])$

$[A]=0.899mol/L$

Hence, the concentration of $N_2O$ in three significant figures will be 0.899 mol/L.

5 0

3 years ago

When electromagnetic radiation above the threshold frequency falls on an object, it emits electrons? a

Bingel [31]

<span>Electromagnetic radiation will be emitted when any object has a temperature above zero. The reason behind this is that atoms within any object at a temperature above absolute zero have energy, and thus is moving.</span>

<span>Atoms are at least partly composed of charged particles, changed particles must be moving too.</span>

8 0

3 years ago

What is the empirical formula for a compound that is 83.7% carbon and 16.3% hydrogen?

zubka84 [21]

Hello!

We use the amount in grams (mass ratio) based on the composition of the elements, see: (in 100 g solution)

C: 83.7% = 83,7 g
H: 16.3% = 16.3 g

Let us use the above mentioned data (in g) and values will be converted to amount of substance (number of moles) by dividing by molecular mass (g / mol) each of the values, lets see:

$C: \dfrac{83.7\:\diagup\!\!\!\!\!g}{12\:\diagup\!\!\!\!\!g/mol} \approx 6.975\:mol$

$H: \dfrac{16.3\:\diagup\!\!\!\!\!g}{1\:\diagup\!\!\!\!\!g/mol} = 16.3\:mol$

We note that the values found above are not integers, so let's divide these values by the smallest of them, so that the proportion is not changed, let's see:

$C: \dfrac{6.975}{6.975} = 1$

$H: \dfrac{16.3}{6.975} \approx 2.3$

Note: So the ratio in the smallest whole numbers of carbon to hydrogen is 3:7, t<span>hus, the minimum or empirical formula found for the compound will be:
</span>
$\boxed{\boxed{C_3H_7}}\end{array}}\qquad\checkmark$

I hope this helps. =)

8 0

3 years ago