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Mazyrski [523]
3 years ago
7

Which element has 3 valence electrons in the 4d sublevel? A. V B. Nb C. Cu D. Tl

Chemistry
2 answers:
Lilit [14]3 years ago
7 0
Nb, the transition metal(d) subshell will always be n-1, meaning the 3d subshell will be in row(period) 4. So if it’s 4d then it is row(period) 5, and if it has 3 valence electrons then the element is located in column V, or the third column in the transition metal section.
scZoUnD [109]3 years ago
4 0

<u>Answer:</u> The correct answer is Option B.

<u>Explanation:</u>

Valence electrons are defined as the electrons which are present in outermost shell of an atom. This is determined by the electronic configuration of an element.

For the given options:

<u>Option A:</u> Vanadium (V)

The atomic number of this atom is 23 and number of electrons that are present are 23. The electronic configuration of vanadium is:

V:[Ar]3d^34s^2

This element does not have 3 electrons in 4d-subshell.

<u>Option B:</u> Niobium (Nb)

The atomic number of this atom is 41 and number of electrons that are present are 41. The electronic configuration of niobium is:

Nb:[Kr]4d^35s^2

This element have 3 electrons in 4d-subshell.

<u>Option C:</u> Copper (Cu)

The atomic number of this atom is 29 and number of electrons that are present are 29. The electronic configuration of copper is:

Cu:[Ar]3d^{10}4s^1

This element does not have 3 electrons in 4d-subshell.

<u>Option D:</u> Thallium (Tl)

The atomic number of this atom is 81 and number of electrons that are present are 81. The electronic configuration of thallium is:

Tl:[Xe]4f^{14}5d^{10}6s^26p^1

This element does not have 3 electrons in 4d-subshell.

Hence, the correct answer is Option B.

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An unknown liquid has a vapor pressure of 88 mmhg at 45°c and 39 mmhg at 25°c. What is its heat of vaporization?
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The anticancer drug Platinol (cisplatin), Pt(NH3)2Cl2, reacts with the cancer cell's DNA and interferes with its growth. (a) Wha
USPshnik [31]

Answer:

(a) = 65.018% (b) = 1.807,83 grams

Explanation:

(a)

The mass % of platinum (pt) in platinol can be obtained applying the general percentage formula (portion of interest / total), in this case the platinol its composed of a single platinum (Pt) mole with molecular weight of 195.088 g/mol, two nitrogen (N)  mole of 28.012 g/mole each. six hydrogen (H) mole of 1.007 g/m and two chlorine (Cl) of 35.453 g/mole

N= 14.006 g/mole x 2 = 28.012

H= 1.0078 g/mole x 6 = 6.046

Cl= 35.453 g/mole x 2 = 70.906

Pt= 195. 088 g/mole x 1 = 195.088

the molecular weight of platinol its = 300.052g

% of Pt in platinol its = ((195.088 g/mole) /(300.052 g/mole))* 100= 65.018%

(b)

Assumption: 851/9 its in fact 851 $/gram

to know how many grams of Platinum can be bought it's necessary to divided the total money between the price of platinum, knowing how many grams can be bought and knowing the percentage of platinum in platinol, it's possible to know how many grams of platinol can be made from $1.00 million

grams of platinum $1'000.000/(851$/g) = 1.175,09 grams of Pt

grams of platinol =

1.175,09 grams of pt/ 0.65018 (grams of pt/grams of platinol)

grams of platinol = 1.807,83 grams of platinol

7 0
4 years ago
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