1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Mazyrski [523]
3 years ago
7

Which element has 3 valence electrons in the 4d sublevel? A. V B. Nb C. Cu D. Tl

Chemistry
2 answers:
Lilit [14]3 years ago
7 0
Nb, the transition metal(d) subshell will always be n-1, meaning the 3d subshell will be in row(period) 4. So if it’s 4d then it is row(period) 5, and if it has 3 valence electrons then the element is located in column V, or the third column in the transition metal section.
scZoUnD [109]3 years ago
4 0

<u>Answer:</u> The correct answer is Option B.

<u>Explanation:</u>

Valence electrons are defined as the electrons which are present in outermost shell of an atom. This is determined by the electronic configuration of an element.

For the given options:

<u>Option A:</u> Vanadium (V)

The atomic number of this atom is 23 and number of electrons that are present are 23. The electronic configuration of vanadium is:

V:[Ar]3d^34s^2

This element does not have 3 electrons in 4d-subshell.

<u>Option B:</u> Niobium (Nb)

The atomic number of this atom is 41 and number of electrons that are present are 41. The electronic configuration of niobium is:

Nb:[Kr]4d^35s^2

This element have 3 electrons in 4d-subshell.

<u>Option C:</u> Copper (Cu)

The atomic number of this atom is 29 and number of electrons that are present are 29. The electronic configuration of copper is:

Cu:[Ar]3d^{10}4s^1

This element does not have 3 electrons in 4d-subshell.

<u>Option D:</u> Thallium (Tl)

The atomic number of this atom is 81 and number of electrons that are present are 81. The electronic configuration of thallium is:

Tl:[Xe]4f^{14}5d^{10}6s^26p^1

This element does not have 3 electrons in 4d-subshell.

Hence, the correct answer is Option B.

You might be interested in
When you are balancing chemical reactions ('equations'), what must you never touch?
timofeeve [1]

You should never touch the subscripts, as that will change the composition. Hope I helped!

8 0
3 years ago
Read 2 more answers
Answer the following question using the reaction: AB ---&gt; A+B
Vadim26 [7]

Answer:

So whats the question?

Explanation:

3 0
3 years ago
Which type of bonding is characterized by overlapping orbitals that allow outer electrons of atoms to move about freely througho
Sonja [21]

Answer:

D metallic

Explanation:

The chemical bonding which rises from electrostatic attractive force between the conduction electrons and the positively charged metal ions is called metallic bonding.

<u>It is sharing of the free electrons among the structure of the positively charged ions which are known as cations. </u>

<u>In this type of bonding, these free electrons freely move in the crystal mattice of the metal.  </u>

The bonding accounts for properties of metals, such as ductility, strength,  electrical and thermal conductivity and resistivity and luster.

6 0
3 years ago
A 25.0 mL sample of sulfuric acid is completely neutralized by adding 32.8 mL of 0.116 mol/L ammonia solution. Ammonium sulfate
Paul [167]

Answer:

0.08 mol L-1

Explanation:

Sulfuric acid Formula: H2SO4

Ammonia Formula: NH3

Ammonium sulfate Formula: (NH₄)₂SO₄

H2SO4 + 2NH3 = 2NH4+ + SO4 2-

H2SO4 + 2NH3 = (NH₄)₂SO₄

H2SO4 = (1/2)x (32.8 x 10^-3 L x 0.116 mol L-1)/25 x 10^-3 L

= 0.08 mol L-1

7 0
2 years ago
If 50 ml of 0.235 M NaCl solution is diluted to 200.0 ml what is the concentration of the diluted solution
Helen [10]

This is a straightforward dilution calculation that can be done using the equation

M_1V_1=M_2V_2

where <em>M</em>₁ and <em>M</em>₂ are the initial and final (or undiluted and diluted) molar concentrations of the solution, respectively, and <em>V</em>₁ and <em>V</em>₂ are the initial and final (or undiluted and diluted) volumes of the solution, respectively.

Here, we have the initial concentration (<em>M</em>₁) and the initial (<em>V</em>₁) and final (<em>V</em>₂) volumes, and we want to find the final concentration (<em>M</em>₂), or the concentration of the solution after dilution. So, we can rearrange our equation to solve for <em>M</em>₂:

M_2=\frac{M_1V_1}{V_2}.

Substituting in our values, we get

\[M_2=\frac{\left ( 50 \text{ mL} \right )\left ( 0.235 \text{ M} \right )}{\left ( 200.0 \text{ mL} \right )}= 0.05875 \text{ M}\].

So the concentration of the diluted solution is 0.05875 M. You can round that value if necessary according to the appropriate number of sig figs. Note that we don't have to convert our volumes from mL to L since their conversion factors would cancel out anyway; what's important is the ratio of the volumes, which would be the same whether they're presented in milliliters or liters.

5 0
2 years ago
Other questions:
  • Bromine is the only nonmetal that is a liquid at room temperature. consider the isotope bromine-81, . select the combination whi
    13·1 answer
  • Fill in the following: Sulfur--32 isotope notation: #p+ : #nº : #e- :
    8·1 answer
  • Write the following numbers in scientific notation.
    14·1 answer
  • Enter the atomic symbol, including mass number and atomic number, for iodine-125.
    10·1 answer
  • What will be the final temperature when a 25.0 g block of aluminum (initially at 25 °C) absorbs 10.0 kJ of heat? The specific he
    5·1 answer
  • CaC2 + 2H2O ⟶ C2H2 + Ca(OH)2
    9·1 answer
  • Atoms of which element below are most likely to gain electrons?
    15·1 answer
  • PLEASE HELP ME<br> What answer is it?
    8·1 answer
  • Can bacteria reproduce
    15·1 answer
  • Which of the following would you rather carry around with you: 15000g of lithium or 15000g palladium?
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!