Need help Write 6/10 as a percent, decimal

A manufacturer finds that in a random sample of 100 of its CD players, 96% have no defects. The manufacturer wishes to make a cl

Marta_Voda [28]

Answer:

At p₀ = 0.982 the manufacturer's claim would not be rejected.

Step-by-step explanation:

The manufacturer wishes to make a claim about the percentage of non-defective CD players and is prepared to exaggerate.

Let the claim made by him be denoted as, p₀.

The hypothesis to test this claim is defined as:

H₀: The proportion of defective is p₀, i.e. p = p₀.

Hₐ: The proportion of defective is less than p₀, i.e. p < p₀.

The significance level of the test is, α = 0.05.

The information provided is:

n = 100

$\hat p$ = 0.96

The test statistic is:

$Z=\frac{\hat p-p_{0}}{\sqrt{\frac{p_{0}(1-p_{0})}{n}}}=\frac{0.96-p_{0}}{\sqrt{\frac{p_{0}(1-p_{0})}{100}}}$

Decision rule:

If the test statistic value is less than the critical value of z, i.e. Z₀.₀₅ = -1.645 (because of the left tail), then the null hypothesis will be rejected. and vice versa.

So, to reject H₀ Z ≤ Z₀.₀₅.

Use hit and trial method.

At p₀ = 0.97 the value of Z is:

$Z=\frac{\hat p-p_{0}}{\sqrt{\frac{p_{0}(1-p_{0})}{n}}}=\frac{0.96-0.97}{\sqrt{\frac{0.97(1-p\0.97)}{100}}}=-0.5862$

At p₀ = 0.98 the value of Z is:

$Z=\frac{\hat p-p_{0}}{\sqrt{\frac{p_{0}(1-p_{0})}{n}}}=\frac{0.96-0.98}{\sqrt{\frac{0.98(1-0.98)}{100}}}=-1.4286$

At p₀ = 0.981 the value of Z is:

$Z=\frac{\hat p-p_{0}}{\sqrt{\frac{p_{0}(1-p_{0})}{n}}}=\frac{0.96-0.981}{\sqrt{\frac{0.981(1-0.981)}{100}}}=-1.5382$

At p₀ = 0.982 the value of Z is:

$Z=\frac{\hat p-p_{0}}{\sqrt{\frac{p_{0}(1-p_{0})}{n}}}=\frac{0.96-0.982}{\sqrt{\frac{0.982(1-0.982)}{100}}}=-1.65474$

At p₀ = 0.982 the value of Z is -1.65474.

Z = -1.65474 > Z₀.₀₅ = -1.645

Thus, at p₀ = 0.982 the manufacturer's claim would not be rejected.

8 0

3 years ago

What is the value of x in the equation Negative StartFraction 2 over 9 EndFraction x = two-fifths? Negative 1 and four-fifths Ne

pogonyaev

Answer:

Option Negative 1 and four-fifths is correct

That is $x=-1\frac{1}{5}$

Step-by-step explanation:

Given problem is Negative start fraction 2 over 9 end fraction x=two-fifths

Given equation can be written as $-\frac{2}{9}x=\frac{2}{5}$

To find the value of x in the given equation :

$-\frac{2}{9}x=\frac{2}{5}$

Mutliply by $\frac{9}{2}$ on both sides we have

$\frac{2x}{9}\times(\frac{9}{2})=\frac{2}{5}\times(\frac{9}{2})$

$-x=\frac{9}{5}$

$x=\frac{-9}{5}$

$x=-1\frac{1}{5}$

therefore the value of x is $-1\frac{1}{5}$

Option Negative 1 and four-fifths is correct

That is $x=-1\frac{1}{5}$

3 0

3 years ago

Read 2 more answers

PLEASE HELP ME 79 POINTS!!!!!!!!!!!!!!!!!!

masya89 [10]

Answer:

Two squares with the same side lengths are always congruent.

Two quadrilaterals with the same side lengths are always congruent.

Two rectangles with the same side lengths are always congruent.

Step-by-step explanation:

7 0

3 years ago

Can i get some help please this is pretty hard

Inessa [10]

Answer:

1. 2/3

2. doesn't exist

3. 2

4. x ≥ 0

5. y ≥ 2

Step-by-step explanation:

If we were to take any two points on the line and divide the difference of the y-coordinates by the difference of the x-coordinates, we'd get the slope. So, take any two points: (0, 2) and (3, 4). The slope is:

(4 - 2) / (3 - 0) = 2/3

The x-intercept is where the line crosses the x-axis, but since the line only starts at (0, 2), the x-intercept doesn't exist.

The y-intercept is where the line crosses the y-axis, which is at point (0, 2) so the y-intercept is 2.

The domain is the possible x-values. Here, because the smallest x-value is 0 (from the point (0,2)), and there is no largest x-value (the arrow at the end of the line indicates the graph goes on to infinity), the domain is: x ≥ 0.

The range is the possible y-values. Here, the smallest possible y value is 2 (from (0, 2)) and the largest is infinity, so the range is: y ≥ 2.

8 0

3 years ago

Read 2 more answers

Provide a detailed description of the given transformation.

Fiesta28 [93]

Answer:

Look below.

Step-by-step explanation:

The following shape is being reflected across the y-axis.

To confirm this, we can check the coordinates.

When something is reflected across the y-axis, its points' y-coordinate don't change. Upon evaluation of the given transformation, we can see that the y-coordinate does not change for any point.

Now, we check the x-coordinate. The x-coordinate MUST be the opposite of the original x-coordinate...

-2 --> 2

-4 --> 4

0 --> 0

-4 --> 4

-2 --> 2

All of the x-coordinates are opposites, and the y-coordinates remained the same, therefore this figure is being reflected across the y-axis.

7 0

3 years ago