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kogti [31]
3 years ago
9

Hilda adds 5 to a number, then multiples the sum by -2. The result is 6. Write and equation to find the number, x. What is the n

umber?
Mathematics
1 answer:
Novay_Z [31]3 years ago
3 0

(x+5)*(-2) = 6

distribute

-2x -10 = 6

add 10 to each side

-2x -10 +10 = 6+10

-2x = 16

divide by -2

-2x/-2 = 16/-2

x = -8

The number is -8

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aiden currently has a balance of $4443.48 in an account he has held for 17 years he open the account with initial deposit of $25
pickupchik [31]
\bf \qquad \textit{Simple Interest Earned Amount}\\\\
A=P(1+rt)\qquad 
\begin{cases}
A=\textit{accumulated amount}\to &\$4443.48\\
P=\textit{original amount deposited}\to& \$2567\\
r=rate\to r\%\to \frac{r}{100}\\
t=years\to &17
\end{cases}
\\\\\\
4443.48=2567(1+r17)\implies \cfrac{4443.48}{2567}=1+17r
\\\\\\
\cfrac{4443.48}{2567}-1=17r\implies \cfrac{\frac{4443.48}{2567}-1}{17}=r\implies 0.043\approx r
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5 0
3 years ago
Simplify: 1(-3.86 + 6.82)| + |(4.02 - 12.45)||
Yuki888 [10]

Answer:

11.39

Step-by-step explanation:

-3.86+6.82=2.96

abs(2.96)=2.96

----------------------

4.02-12.45=-8.43

abs(-8.43)=8.43

-----------------------

1(2.96)+8.43=2.96+8.43=11.39

6 0
3 years ago
Which of the following probabilities is equal to approximately 0.2957? Use the portion of the standard normal table below to
devlian [24]

Answer: It is C on edginuity.

Step-by-step explanation:

got it right

6 0
3 years ago
Read 2 more answers
The 3 × 3 matrix P satisfies the matrix equation P^2 = P.
riadik2000 [5.3K]

Answer:  The answers are given below.

Step-by-step explanation:  Given that a  3 × 3 matrix P satisfies the matrix equation P² = P.

We are to

(a) find the possibilities for the determinant of P.

(b) explain the reason behind there are no other possibilities.

(c) give an example of P, for each possible determinant.

(a) According to the given information, we have

P^2=P\\\\\Rightarrow P^2-P=0\\\\\Rightarrow P(P-I)=0\\\\\Rightarrow P=0,~~~P=I.

So, P can be either a zero matrix of order 3 or an identity matrix of order 3.

If P = 0, then det(P) = 0     and     if P = I, then det(P) = 1.

Therefore the possible determinants of P are 0 and 1.

(b) There can be any other determinant other than 0 and 1, because if so, then the given equation P² = P will not be satisfied.

(c) If |P| = 0, then the matrix P can be can be of the form as follows:

P=\left[\begin{array}{ccc}0&0&0\\0&0&0\\0&0&0\end{array}\right] .

If |P| = 1, the the matrix P can be of the form as follows :

P=\left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right] .

Thus, all the parts are answered.

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3 years ago
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If AB is 128 centimeters long what is xe
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