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egoroff_w [7]
3 years ago
10

BRAINLIEST ANSWER!!!!!!!!!!!!!!!!!!!

Physics
2 answers:
disa [49]3 years ago
5 0
Im going to say it is the first one; <span>A home is a non-living habitat that has living inhabitants. </span>
zhuklara [117]3 years ago
4 0
Home is like a shelter where it keeps us safe.
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Object A has mass 83.0 g and hangs from an insulated thread. When object B, which has a charge of +140 nC, is held nearby, A is
erastova [34]

Answer:

a) -238 nC  

b) 0.889 N  

Explanation:

Concepts and Principles

<u>Particle in Equilibrium:</u> If a particle maintains a constant velocity (so that a = 0), which could include a velocity of zero, the forces on the particle balance and Newton's second law reduces to:  

∑F = 0                                                                           (1)  

<u>Coulomb's Law:</u> the magnitude of the electrostatic force exerted by a point charge q1 on a second point charge q2 separated by a distance r is directly proportional to the product of the two charges and is inversely proportional to the square of the distance between them:

F_12 = k*| q1 |*| q2 |/r^2                                                 (2)

where k = 8.99 x 10^9 N  m^2/C^2 is Coulomb constant.  

<u>Given Data  </u>

<em>mA (mass object A) = (83 g)*(1/1000g)=0.09 kg </em>

<em>qB (charge of object B) = (140 nC)*(1/10^9 nC) = 130 x 10^-9 C </em>

<em>Object A is attracted to object B. </em>

<em>Ф(angle made by object A with the vertical) = 7.2°  </em>

<em>(  r (distance between the two objects) = (5 cm) * (1 m/ 100 cm) =0.05 m  </em>

<em>Object A is in equilibrium.  </em>

Required Data

In part (a), we are asked to determine the charge qA of object A.

In part (b), we are asked to determine the tension T in the thread.  

(a) The FBD in Figure 1 shows the forms acting on object A; Fe is the electric force exerted on object A by object B, T is the tension force exerted on the thread, and m_a*g is the gravitational force exerted on object A.  

Model object A as a particle in equilibrium in the horizontal and vertical direction and apply Equation (1) to it:  

∑F_x = F_e-Tsin = 0                                   F_e=Tsin<em>Ф                </em><em>(3)</em>

∑F_y = Tcos<em>Ф - </em>m_a*g= 0                      m_a*g=Tsin<em>Ф                </em><em>(4)</em>

Divide Equation (3) by Equation (4) to eliminate T:

F_e/m_a*g=tan<em>Ф</em>

F_e=m_a*g*tan<em>Ф</em>

Substitute for  F_e by using Coulomb's law from Equation (2):

k*| q_A |*| q_B |/r = m_a*g*tan<em>Ф</em>

Solve for q_A :  

| q_A | = m_a*g*tanФ_r/k*| q_B |

Substitute numerical values from given data:

| q_A | =  238 nC  

Because object A is attracted to object B. it has an opposite negative charge. Therefore, the charge on object A is | q_A | =  -238 nC  

(b)  

Solve Equation (4) for T:  

T = m_a*g/cosФ

Substitute numerical values from given data:

T = (0.09 kg)(9.8 m/s^2) /cos 7.2°  

  = 0.889 N  

4 0
3 years ago
Our data for how much force is needed can be qualitative. This means we don’t have to know exact values for the force in Newtons
kirill [66]

Answer:

For macroscopic objects, we use units such as grams and kilograms to state their masses, but. There will not be much error if you estimate the mass of an atom by simply. to what we did for our hypothetical example, but the percentages are different: Add two atomic masses of carbon and six atomic masses of hydrogen:

Explanation:

8 0
2 years ago
Read 2 more answers
Adam and Natalie push on a cart using 150 N of force.The cart does not move.What is static friction on the cart?
Roman55 [17]

When force is applied on an object the object will not slide

So here object will remain in equilibrium after applying the force

So in this case the condition of equilibrium is maintained due to friction force that is applied on the object.

So here for equilibrium be can say

F_{net} = 0

also we know that

F_{net} = F - F_f

we are given that

F = 150 N ( applied force on the box)

F_{net} = 150 - F_f = 0

F_f = 150 N

So here this friction force on the cart is known as static friction

F_s = 150 N

4 0
3 years ago
Read 2 more answers
Aunt Mary needs to hang a picture in her bedroom. She uses a hammer to drive the nail into the wall. Find the force exerted by t
Cerrena [4.2K]

t = time of contact of hammer with the nail = 0.4 sec

I = impulse exerted by the hammer on the nail = 32 N s

F = force applied by the hammer on the nail

we know that , impulse is given as

I = F t                  where I = impulse , F = force , t = time

hence the impulse of hammer on nail is given as

I = F t

inserting the values

32 Ns = F (0.4 sec)

F = 32/0.4

F = 80 N

hence the force exerted by the hammer comes out to be 80 N


4 0
3 years ago
if a caterpillar is moving in a straight line at a speed of 7 cm/s, how long will it take the caterpillar to reach a green, leaf
Shkiper50 [21]
At the speed of 8 cm/s
8 0
3 years ago
Read 2 more answers
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