3 years ago

Unit 2 kinetic energy mastery test

Physics

1 answer:

erma4kov [3.2K]3 years ago

4 0

Answer: kinetic energy is Energy of motion.

Explanation:

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For a wire has a circular cross section with a radius of 1.23mm.

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Answer:

$5.731\times 10^{-5}\ m/s$

Decrease

Explanation:

I = Current = 3.7 A

e = Charge of electron = $1.6\times 10^{-19}\ C$

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$v_d$ = Drift velocity of electrons

r = Radius = 1.23 mm

Current is given by

$I=neAv_d\\\Rightarrow v_d=\dfrac{I}{neA}\\\Rightarrow v_d=\dfrac{3.7}{8.49\times 10^{28}\times 1.6\times 10^{-19}\times \pi (1.23\times 10^{-3})^2}\\\Rightarrow v_d=5.731\times 10^{-5}\ m/s$