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alisha [4.7K]
3 years ago
10

The native range of a species includes all areas in ahich it lives

Biology
2 answers:
lukranit [14]3 years ago
8 0

The answer is false.

Nata [24]3 years ago
7 0
True!

The native range of a species includes all areas where that species lives. It also includes temporary areas, such as summer or winter range, breeding or non-breeding range. The native range is the area in which species can be found during the lifetime.
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If the frequency of the recessive allele for a gene is 0.3, calculate the expected frequency of heterozygotes in the next genera
Kisachek [45]
Q = recessive allele frequency = 0.3, and thus in H-W equilibrium there are ONLY two alleles, q (recessive) and
p (dominant). Therefore all of the p and q present for this gene in a population must account for 100% of this gene's alleles. And 100% = 1.00.
So p, the dominant allele frequency, must be equal to 1 - q --> p = 1 - q
p = 1 - 0.3 = 0.7.
Since heterozygotes are a combination of the p and q, we must again look at the frequencies of each genotype: p + q = 1, then (p+q)^2 = 1^2
So multiplying out (p+q)(p+q) = 1, we get: p^2+2pq+q^2 = 1 (all genotypes), where p^2 = frequency of homozygous dominant individuals, 2pq = frequency of heterozygous individuals, and q^2 = frequency of homozygous recessive individuals.
Therefore if the population is in H-W equilibrium, then the expected frequency of heterozygous individuals = 2pq = 2(0.7)(0.3)
2pq = 2(0.21) = 0.42, or 42% of the population.
Hope that helps you to understand how to solve population genetics problems!
7 0
3 years ago
Compare and Contrast competitive inhibition and and Allosteric inhibition
gizmo_the_mogwai [7]

Competitive inhibition vs allosteric inhibition

In competitive the substrate and inhibitor bind at the same active site - pretty straightforward. In allosteric regulation (speaking specifically about inhibition here), the inhibitor is binding at a site other than the active site, and changing the enzyme in some way to make it inactive.


3 0
3 years ago
How can a mother with the B blood type, having A antibodies in her plasma, carry a baby full-term that inherits the A blood type
DanielleElmas [232]

Answer:

The mother can carry a full-term baby with A blood type because the mother's blood does not mix with the baby's blood, so the mother's immune system does not activate attacking the baby.

Explanation:

The reason why a mother with B blood type and A antibodies in her system can carry a full-term pregnancy is thanks to the placenta. The placenta is a shared organ between the mother and the baby. Its function is to protect the baby and produce the necessary exchanges of nutrients and wastes between the maternal blood and the baby's blood. As the two types of blood are separated, and they never get in contact during pregnancy, the immune system of the mother does not recognize the baby as a treat. The mother can have A antibodies in her plasma due to a previous pregnancy where during delivery, the two types of blood mixed, also it can be due to any contact with the A blood type. When the foreign blood enters the body, the immune system forms antibodies for it.

4 0
3 years ago
with regard to enzymes, what can be said to the relationship between the substance and the active site?
77julia77 [94]
The substrate and the active site both need to fit together perfectly in order for the enzyme to work properly. If their shape is changed, typically through heat or a change in pH, the enzyme will not work.
7 0
3 years ago
Read 2 more answers
How to minimize flood​
Luda [366]

Answer:

some of the ways are...

Explanation:

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3 0
3 years ago
Read 2 more answers
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