Answer: The molecular formula will be
Explanation:
If percentage are given and we are given total mass is 100 grams.
So, the mass of each element is equal to the percentage given.
Mass of C= 31.17 g
Mass of H = 6.54 g
Mass of O = 62.29 g
Step 1 : convert given masses into moles.
Moles of C =
Moles of H=
Moles of O =
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For C=
For H =
For O =
The ratio of C: H: O= 1: 2.5: 1.5
Converting them into whole number ratios by multiplying by 2.
Hence the empirical formula is
The empirical weight of = 2(12)+5(1)+3(16)= 77 amu
The molecular weight = 231.2 amu
Now we have to calculate the molecular formula.
The molecular formula will be=
The molecular formula will be
<span>56.30
The atomic mass of Ag is 107.87. The atomic mass of Cl is 35.45. The molecular mass of AgCl is therefore 143.32. 0.025 mols of AgCl were produced. This required .0125 mols of the original metal chloride since it has 2 chlorine atoms per molecule and AgCl only has one per molecule.
The molecular mass of mCl2 must be 127.2 in order for 1.59g of mCl2 to be .0125 mols. The molecular mass of m can be calculated by subtracting the molecular mass of 2 chlorine atoms
127.2-35.45-35.45=56.30</span>
Answer:
<h2>mass = 19.98 g</h2>
Explanation:
To find the mass of 1.11 mol of H2O we must first find it's molecular mass after that we use the formula
<h3>m = M × n</h3>
where
m is the mass
M is the molecular mass
n is the number of moles
From the question
n = 1.11 mol
Taking
M( H) = 1 g/mol , M(O) = 16 g/mol
We have
M( H2O) = 2 + 16 = 18 g/mol
So we have
m = 1.11 × 18
We have the final answer as
<h3>mass = 19.98 g</h3>
Hope this helps you