In this synthesis reaction, what product will form?

Describe and explain one real-life and/or recent example of how scientific knowledge had to change or adapt in the face of new d

AfilCa [17]

Answer: Science is a particular way of knowing about the world. In science, explanations are restricted to those that can be inferred from confirmable data—the results obtained through observations and experiments that can be substantiated by other scientists. Anything that can be observed or measured is amenable to scientific investigation. Explanations that cannot be based on empirical evidence are not a part of science.

Explanation:

4 0

3 years ago

For the following galvanic cell, represented in line notation, determine what balanced half-reactions occur at each electrode. (

Alex787 [66]

Answer:

Anode (oxidation): Cr(s) ⇒ Cr³⁺(aq) + 3 e⁻

Cathode (reduction): Ag⁺(aq) + 1 e⁻ ⇒ Ag(s)

Explanation:

Let's consider the notation of a galvanic cell.

Cr(s) | Cr³⁺(aq) || Ag⁺(aq) | Ag(s)

On the left, it is represented the anode (oxidation) and on the right, it is represented the cathode (reduction).

The half-reactions are:

Anode (oxidation): Cr(s) ⇒ Cr³⁺(aq) + 3 e⁻

Cathode (reduction): Ag⁺(aq) + 1 e⁻ ⇒ Ag(s)

To have the global reaction, we have to multiply the reduction by 3 (so the number of electrons gained and lost are the same) and add both half-reactions.

Global reaction: Cr(s) + 3 Ag⁺(aq) ⇒ Cr³⁺(aq) + 3 Ag(s)

6 0

3 years ago

Calcium<br> and what <br> makes bones hard

Ira Lisetskai [31]

Bones are made up of a framework of a protein called collagen , with a mineral called calcium phosphate that makes the framework hard and strong. Bones store calcium and release some into the bloodstream when it's needed by other parts of the body.

5 0

3 years ago

What mass of lithium phosphate would you mass to make 2.5 liter of 1.06 M lithium

alex41 [277]

Answer:

Approximately $3.06 \times 10^{2}\; \rm g$ (approximately $306\; \rm g$ .)

Explanation:

Calculate the quantity $n$ of lithium phosphate in $V = 2.5\; \rm L$ of this $c = 1.06\; \rm M = 1.06\; \rm mol \cdot L^{-1}$ lithium phosphate solution.

$\begin{aligned}n &= c \cdot V\\ &= 2.5\; \rm L \times 1.06\; mol \cdot L^{-1}\\ &= 2.65\; \rm mol\end{aligned}$ .

Empirical formula of lithium phosphate: $\rm Li_3PO_4$ .

Look up the relative atomic mass of $\rm Li$ , $\rm P$ ,and $\rm O$ on a modern periodic table:

$\rm Li$ : $6.94$ .
$\rm P$ : $30.974$ .
$\rm O$ : $15.999$ .

Calculate the formula mass of $\rm Li_3PO_4$ :

$M(\rm Li_3PO_4) = 3 \times 6.94 + 30.974 + 4 \times 15.999 = 115.79\; \rm g \cdot mol^{-1}$ .

Calculate the mass of that $n = 2.65\; \rm mol$ of $\rm Li_3PO_4$ formula units:

$\begin{aligned}m &= n \cdot M \\ &= 2.65\; \rm mol \times 115.79\; \rm g\cdot mol^{-1} \\ &\approx 3.06 \times 10^{2}\; \rm g \end{aligned}$ .

5 0

3 years ago

Blast furnaces extra pure iron from the iron(III) oxide in iron ore in a two step sequence. In the first step, carbon and oxygen

aleksklad [387]

Answer:

The mass of O2 that will produce 10 g of Iron, Fe is 6.0 g

Note: The question is missing some details. The complete question is given below:

Blast furnaces extra pure iron from the iron (III) oxide in iron ore in a two step sequence. In the first step, carbon and oxygen react to form carbon monoxide 2C(s)+O2(e) -2CO(« In the second step, iron(III) oxide and carbon monoxide react to form iron and carbon dioxide Fe2O3(s) + 3 CO(g) → 2 Fe(s) + 3CO2(g) Suppose the yield of the first step is 90.% and the yield of the second step is 79.%. Calculate the mass of oxygen required to make 10 g of iron. Be sure your answer has a unit symbol, if needed, and is rounded to the correct number of significant digits.

Explanation:

Equation for the two reactions is given below:

Step 1: 2C(s) + O2(g) → 2CO(g)

Step 2: Fe2O3(s) + 3CO(g) → 2Fe(s) + 3CO2(g)

In the second step 3 moles of CO reacts to produce 2 moles of Fe

Molar mass of CO = 28 g/mol, molar mass of Fe = 56 g/mol

Therefore, 84 g (3 × 28) of CO will produce 112 g (2 × 56) of Fe

10 g of Fe will be produced by 84/112 × 10 g of CO = 7.5 g of CO

However, the actual yield is 79%, therefore, 7.5 g of CO will produce 0.79 × 10 g of Fe = 7.9 g of Fe

Mass of CO that will produce an actual yield of 10 g of Fe = 7.5/7.9 × 10 = 9.50 g of CO

From the first step:

1 mole of O2 reacts to produce 2 moles of CO (molar mass of O2 = 32 g)

32 g of O2 produces 56 g (2 × 28 g) of CO

Mass of O2 that will produce 9.50 g of CO = 32/56 × 9.50 g = 5.43g

However, since the actual yield is 90%, therefore, mass of CO produced = 0.9 × 9.50 = 8.55 g of CO

Mass of O2 that will produce 9.50 g of CO = 5.43/8.55 × 9.50 g = 6.03 g

Therefore, mass of O2 that will produce 10 g of Iron, Fe is 6.0 g

5 0

3 years ago