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KIM [24]
3 years ago
6

What dose iff mean when used in a biconditional statement

Chemistry
1 answer:
katovenus [111]3 years ago
4 0

Hello!

A biconditional statement is when one conditional statement and it's converse is true.

A conditional statement is an "If <em>hypothesis</em>, then <em>conclusion</em>" statement.

A converse statement is an "If <em>conclusion</em>, then <em>hypothesis</em>" statement.

Looking at this, both of these statements have their hypothesis and conclusion switched.

Thus, a biconditional statement is a "<em>Hypothesis</em> IFF <em>conclusion</em>." In this statement, IFF means if and only if.

Therefore, when IFF is used in a biconditional statement, it means if and only if.

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How do chemists use systems and order in their work?
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3 years ago
What mass of zinc (molar mass 65.4 g moll) does it take to produce 0.50 mole of H2(g)?
Hatshy [7]

Answer:

32.7 g of Zn

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

Zn + 2HCl —> ZnCl₂ + H₂

From the balanced equation above,

1 mole of Zn reacted to produce 1 mole of H₂

Next, we shall determine the number of mole of Zn required to produce 0.5 mole of H₂. This can be obtained as follow:

From the balanced equation above,

1 mole of Zn reacted to produce 1 mole of H₂.

Therefore, 0.5 mole of Zn will also react to produce to 0.5 mole of H₂.

Thus, 0.5 mole of Zn is required.

Finally, we shall determine the mass of 0.5 mole of Zn. This can be obtained as follow:

Mole of Zn = 0.5 mole

Molar mass of Zn = 65.4 g/mol

Mass of Zn =?

Mass = mole × molar mass

Mass of Zn = 0.5 × 65.4

Mass of Zn = 32.7 g

Thus, 32.7 g of Zn is required to produce 0.5 mole of H₂.

4 0
2 years ago
How many grams of solute are needed to prepare a 3.50% mass/mass solution that has a solution mass of 2.50x102 grams.
Elis [28]
One way of expressing concentration is by percent. It may be on the basis of mass, mole or volume. Percent is expressed as the amount of solute per amount of the solution. For this case, we are given the percent by mass. In order to solve the amount of solute, we multiply the percent with the amount of the solution.

Mass of solute = percent by mass x mass solution
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5 0
3 years ago
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