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Alex17521 [72]
2 years ago
5

Question help a lottery game has balls numbered 0 through 1313. what is the probability of selecting an even numbered ball or a

33â
Mathematics
1 answer:
Licemer1 [7]2 years ago
7 0
So i'm assuming 33^a is saying any number that is a square of 33 inside of 1,313 so first, to find how many even numbers divide 1,313 by two to get 656.5 so if I am not mistaken 656 numbers in 1,313 will be even. Now find all squares of 33 that don't pass 1,313 which is 33 itself and 1,089 because 33^3 is 35,937 so add 2 to 656 to get 668. so the probability is 658/1,313 i believe.
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Alison is learning how to walk. 50% of the time that she takes a step she falls down. Her older brother wants to design a simula
MissTica

Answer with explanation:

Alison is learning how to walk.50% of times she takes a step she falls down.

Probability of falling down in next step =\frac{50}{100}=\frac{1}{2}

Probability of not falling down in next step =\frac{50}{100}=\frac{1}{2}

From ,the four option given,we have to find the best simulation which her older brother wants to design a simulation to find the probability that she will fall down 5 out of the next 7 times she tries to take step.

While Simulating the Probability of falling down should be =\frac{5}{7}

And , probability of not falling down1-\frac{5}{7}=\frac{2}{7}

→→⇒F=Falling, NF=Non Falling

A) Roll a die letting 1 represent Alison falling and 2-6 represent Alison not falling. Roll the die five times.

P(F)=\frac{1}{6},P(NF)=\frac{5}{6}

Incorrect option,probabilities of falling and non falling does not match with Actual probability of falling and non falling.  

B) Roll a die letting 1 represent Alison falling and 2-6 represent Alison not falling. Roll the die seven times.

P(F)=\frac{1}{6},P(NF)=\frac{5}{6}

Incorrect option,probabilities of falling and non falling does not match with Actual probability of falling and non falling.

C) Let Heads represent Alison falling down and Tails representing Alison not falling down. Flip the coin five times.

P(F)=\frac{1}{2},P(NF)=\frac{1}{2}

Simulation is done only five times , that is coin has been flipped only five times.it must have been flipped seven times.Incorrect option.  

D) Let Heads represent Alison falling down and Tails representing Alison not falling down. Flip the coin seven times.

P(F)=\frac{1}{2},P(NF)=\frac{1}{2}

Simulation is done seven times , that is coin has been flipped seven times.So,she should fall 5 times that is head should appear 5 out of seven times, and tail should appear 2 out of seven times.correct option.

Option D

4 0
3 years ago
Read 2 more answers
What is the solution to the following equation?<br><br> 5 + 3 (y - 4) = 4y +10
Umnica [9.8K]

Answer:

5 +3(y-4) = 4y +10

5 + 3y -12= 4y +10

-7 +3y = 4y + 10

3y - 4y = 10 + 7

-y = 17

y= -17

8 0
2 years ago
Read 2 more answers
2) The management company of a popular, but unstable, rapper is worried about their investment
Lyrx [107]

Answer:

137,000

Step-by-step explanation:

its math bro

5 0
3 years ago
Part B: Your cell phone and tablet use the same account. The cell phone costs $0.10 for
Oksanka [162]

The inequalities are x + y < 5000 and 0.10x + 0.15y ≤ $450 which shows each month, you want to only spend up to $450 and use less than 5,000 minutes on both of the devices.

<h3>What is inequality?</h3>

Inequality is defined as a mathematical expression in which both sides are not equal and have mathematical signs that are either less than or greater than.

Let's suppose the total minutes of uses for cell phone is x

and total minutes of uses of for tablet is y

Cell phone cost $0.10 each minute and tablet cost $0.15 each minute.

Then total minutes will be:

x + y < 5000 (as it is given that the time will be less than 5,000 minutes on both of the devices)

And total cost = $450

0.10x + 0.15y ≤ $450

Thus, the inequalities are x + y < 5000 and 0.10x + 0.15y ≤ $450 which shows each month, you want to only spend up to $450 and use less than 5,000 minutes on both of the devices.

Learn more about the inequality here:

brainly.com/question/19491153

#SPJ1

7 0
2 years ago
HELPPP ASAPPP PLAESE HELPP
bogdanovich [222]
2 3 1 hope this helps
8 0
2 years ago
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