Answer:
a) 615
b) 715
c) 344
Step-by-step explanation:
According to the Question,
- Given that, A study conducted by the Center for Population Economics at the University of Chicago studied the birth weights of 732 babies born in New York. The mean weight was 3311 grams with a standard deviation of 860 grams
- Since the distribution is approximately bell-shaped, we can use the normal distribution and calculate the Z scores for each scenario.
Z = (x - mean)/standard deviation
Now,
For x = 4171, Z = (4171 - 3311)/860 = 1
- P(Z < 1) using Z table for areas for the standard normal distribution, you will get 0.8413.
Next, multiply that by the sample size of 732.
- Therefore 732(0.8413) = 615.8316, so approximately 615 will weigh less than 4171
- For part b, use the same method except x is now 1591.
Z = (1581 - 3311)/860 = -2
- P(Z > -2) , using the Z table is 1 - 0.0228 = 0.9772 . Now 732(0.9772) = 715.3104, so approximately 715 will weigh more than 1591.
- For part c, we now need to get two Z scores, one for 3311 and another for 5031.
Z1 = (3311 - 3311)/860 = 0
Z2 = (5031 - 3311)/860= 2
P(0 ≤ Z ≤ 2) = 0.9772 - 0.5000 = 0.4772
approximately 47% fall between 0 and 1 standard deviation, so take 0.47 times 732 ⇒ 732×0.47 = 344.
Six million, seven thousand two hundred
Answer:
x= -5/3
Step-by-step explanation:
Move all the terms that don't contain x to the right side and solve.
Hope this helps :)
Answer:
the answer is -10
Step-by-step explanation:
Its basically multiplication
Answer:
92776
Step-by-step explanation:
From the given question,
The analysis of the given question can be computed as follows:
I have 5 digits
My name is worth 90000
my two is worth 2000
one of my seven is worth 70
and the other is worth 10 times
as much i.e 10× 70 = 700 700
my other digit is six 6
What number am I?
So, we are expected to look for the summation of all the numbers
i.e 90000 + 2000 + 70 + 700 + 6
= 92776
Thus, the number is 92776
