Question

What is the y intercept of this line y+4=-4(x-2)

Answer 1

Y + 4 = -4 (x - 2)

Y - INTERCEPT:
y + 4 = -4 ((0) - 2)
y + 4 = -4 (-2)
y + 4 = 8
y = 4
(0, 4)

STANDARD FORM:
Ax + By = C
y + 4 = -4x + 8
4x + y + 4 = 8
4x + y = 4

X INTERCEPT:
(0) + 4 = -4 (x - 2)
4 = -4 (x - 2)
4 = -4x +8
-4 = -4x
x = 1
(1, 0)

PERPINDICULAR LINE:
y + (1) = (1/4) (x - (5))
y + 1 = 1/4x - 5/4
-1/4x + y + 1 = -5/4
-1/4x + y = -9/4
x - 4y = 9

X INTERCEPT OF PERPINDICULAR LINE:
x - 4(0) = 9
x - 0 = 9
x = 9
(9, 0)

PARALLEL LINE:
y + (-2) = -4 (x - (0))
y - 2 = -4x + 0
4x +  y - 2 = 0
4x + y = 2

ORDERED PAIR FOR PARALLEL LINE:
4(-2) + y = 2
-8 + y = 2
y = 10
(-2, 10)