Let x represent the number of liters of 50% acid Theresa puts into the mix. The the number of liters of 30% acid will be (420-x). The total amount of acid in the final solution will be ...
0.50x + 0.30(420-x) = 0.45(420)
0.20x + 126 = 189 . . . . . . . . . . . . . . . simplify
0.20x = 63 . . . . . . . . . . . . . . . . . . . . . subtract 126
x = 63/0.20 = 315 . . . . . . . . . . . . . . . liters of 50% solution
(420-x) = 420-315 = 105 . . . . . . . . . liters of 30% solution
Theresa should mix ...
105 liters of 30% solution
315 liters of 50% solution
Mom drove for 11 hours.
Dad drove for 3 hours.
<u>Step-by-step explanation</u>:
- Total distance = 895 miles
- Mom drove a speed of 65 mph
- Dad drove a speed of 60 mph
Let 'x' be the number of hours drove by mom.
Let 'y' be the number of hours drove by dad.
x + y = 14 ---------------(1)
65x + 60y = 895 ---------(2)
Multiply eq(1) by 60 and subtract eq(2) from (1),
60x + 60y = 840
-(<u>65x + 60y = 895</u>)
<u> -5x = -55 </u>
x = 55/5
x = 11
∴ Mom drove for 11 hours.
Substitute x=11 in eq(1)
11+y = 14
y = 3
∴ Dad drove for 3 hours.
Answer:
Step-by-step explanation:
That '5' in f(5x) will compress the graph of x^2 horizontally.
If you were to graph f(x) = x^2, you'd get a parabolic graph; the parabola will open UP.
Suppose you graphed f(x) = x^2 on the interval [-4, 4].
Then the graph of g(x) = f(5x) would be graphed on the interval [-4/5, 4/5]. In other words, the graph would be on a shorter interval, one shorter by a factor of 5.
The solution to the given expression negative four and one third ÷ two and one fifth is -1 32/33
<h3>Fraction division</h3>
negative four and one third ÷ two and one fifth
-4 1/3 ÷ 2 1/5
= -13/3 ÷ 11/5
- Multiply by the reciprocal of 11/5
- The reciprocal of 11/5 is 5/11
= -13/3 × 5/11
= (-13 × 5) / (3 × 11)
= -65 / 33
= -1 32/33
Therefore, the solution to the fraction is -1 32/33
Learn more about fraction:
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Answer:
The value of b is 3
Step-by-step explanation:
mx is the slope and b is the y intercept. I hope this helps!