All categories

2 years ago

You go down 8 floors down your friend goes up 5 floors write each amount as an integer

Mathematics

1 answer:

Westkost [7]2 years ago

6 0

(-8)+5

******************

You might be interested in

Division 54 /7.5 plz answer this

harkovskaia [24]

Answer:

turn the decimal into a whole number by multiplying by 10, 100 (what you do to one number you must do to the other)

multiply both by 10 it then becomes

540/75 = 7.2

it's easier to divide whole numbers and is the same answer as 54/7.5

6 0

2 years ago

Is X=3 calculate the value of X3+X btw the 3 is a small three

Naddik [55]

The only 'small number' that I know that would affect the answer is an exponent that looks like ³ so the problem would be x³+x

remember that x³=x times x times x
if x=3 then
3³+3=27+3=30

3 0

2 years ago

Read 2 more answers

in a class there are 115 students going on a field trip 2/5 are bringing a notebook on the field trip how many students are brin

xxMikexx [17]

Answer:

Step-by-step explanation:

(2/5)*115

230/5

46 students

4 0

2 years ago

<img src="https://tex.z-dn.net/?f=prove%20that%5C%20%20%5Ctextless%20%5C%20br%20%2F%5C%20%20%5Ctextgreater%20%5C%20%5Cfrac%20%7B

inysia [295]

$\large \bigstar \frak{ } \large\underline{\sf{Solution-}}$

Consider, LHS

$\begin{gathered}\rm \: \dfrac { \tan \theta + \sec \theta - 1 } { \tan \theta - \sec \theta + 1 } \\ \end{gathered}$

We know,

$\begin{gathered}\boxed{\sf{ \:\rm \: {sec}^{2}x - {tan}^{2}x = 1 \: \: }} \\ \end{gathered} \\ \\ \text{So, using this identity, we get} \\ \\ \begin{gathered}\rm \: = \:\dfrac { \tan \theta + \sec \theta - ( {sec}^{2}\theta - {tan}^{2}\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered}$

We know,

$\begin{gathered}\boxed{\sf{ \:\rm \: {x}^{2} - {y}^{2} = (x + y)(x - y) \: \: }} \\ \end{gathered} \\$

So, using this identity, we get

$\begin{gathered}\rm \: = \:\dfrac { \tan \theta + \sec \theta - (sec\theta + tan\theta )(sec\theta - tan\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered}$

can be rewritten as

$\begin{gathered}\rm\:=\:\dfrac {(\sec \theta + tan\theta ) - (sec\theta + tan\theta )(sec\theta -tan\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:\dfrac {(\sec \theta + tan\theta ) \: \cancel{(1 - sec\theta + tan\theta )}} { \cancel{ \tan \theta - \sec \theta + 1} } \\ \end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:sec\theta + tan\theta \\\end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:\dfrac{1}{cos\theta } + \dfrac{sin\theta }{cos\theta } \\ \end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:\dfrac{1 + sin\theta }{cos\theta } \\ \end{gathered}$

<h2>Hence,</h2>

$\begin{gathered} \\ \rm\implies \:\boxed{\sf{ \:\rm \: \dfrac { \tan \theta + \sec \theta - 1 } { \tan \theta - \sec \theta + 1 } = \:\dfrac{1 + sin\theta }{cos\theta } \: \: }} \\ \\ \end{gathered}$

$\rule{190pt}{2pt}$

5 0

1 year ago

A toxic radioactive substance with the density of 4 mg/cm² is detected in the been detected in the ventilating ducts that was us

Kruka [31]

The formula for half-life is:

$A = P(0.5)^{t/h}$

A is the amount remaining, P is the initial amount, t is the time that has passed, and h is the half-life of the substance. Plug in the values that you know and solve:

$4 = P(0.5)^{35/20} \\ \\ 4 = P(0.5)^{1.75} \\ \\ P = \frac{4}{0.5^{1.75}} \\ \\ P \approx 13.4543426441$

Rounded to the nearest whole number, the density of the substance was about 13<span>mg / cm².</span>

8 0

2 years ago