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ahrayia [7]
3 years ago
13

How to factor 4(x+5)^3(x-1)^2-(x+5)^4 • 2 (x-1) by grouping?

Mathematics
1 answer:
nata0808 [166]3 years ago
5 0
\bf 4(x+5)^3(x-1)^2-(x+5)^4\cdot 2(x-1)
\\\\\\
4(x+5)^3(x-1)^2-2(x-1)(x+5)^4
\\\\\\ \underline{2}\cdot 2\underline{(x+5)^3}(x-1)\underline{(x-1)}~-~\underline{2}\underline{(x-1)}(x+5)\underline{(x+5)^3}\leftarrow 
\begin{array}{llll}
notice~the\\
common\\ \underline{factors}
\end{array}
\\\\\\
2(x+5)^3(x-1)~[~2(x-1)-(x+5)~]
\\\\\\
2(x+5)^3(x-1)~[2x-2-x-5]\implies 2(x+5)^3(x-1)(x-7)
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Step-by-step explanation:

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2 years ago
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N76 [4]

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viva [34]

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