Answer:
<h2>no real solution</h2>
Step-by-step explanation:
![-3x^2-4x-4=0\qquad\text{change the signs}\\\\3x^2+4x+4=0\\\\\text{use the quadratic formula:}\\\\\text{for}\ ax^2+bx+c=0\\\\\text{if}\ b^2-4ac0,\ \text{then an equation has two solutions:}\ x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}](https://tex.z-dn.net/?f=-3x%5E2-4x-4%3D0%5Cqquad%5Ctext%7Bchange%20the%20signs%7D%5C%5C%5C%5C3x%5E2%2B4x%2B4%3D0%5C%5C%5C%5C%5Ctext%7Buse%20the%20quadratic%20formula%3A%7D%5C%5C%5C%5C%5Ctext%7Bfor%7D%5C%20ax%5E2%2Bbx%2Bc%3D0%5C%5C%5C%5C%5Ctext%7Bif%7D%5C%20b%5E2-4ac%3C0%2C%5C%20%5Ctext%7Bthen%20an%20equation%20has%20no%20solution%7D%5C%5C%5C%5C%5Ctext%7Bif%7D%5C%20b%5E2-4ac%3D0%2C%5C%20%5Ctext%7Bthen%20an%20equation%20has%20one%20solution%7D%5C%20x%3D%5Cdfrac%7B-b%7D%7B2a%7D%5C%5C%5C%5C%5Ctext%7Bif%7D%5C%20b%5E2-4ac%3E0%2C%5C%20%5Ctext%7Bthen%20an%20equation%20has%20two%20solutions%3A%7D%5C%20x%3D%5Cdfrac%7B-b%5Cpm%5Csqrt%7Bb%5E2-4ac%7D%7D%7B2a%7D)
![\text{We have}\ a=3,\ b=4,\ c=4.\\\\\text{Substitute:}\\\\b^2-4ac=4^2-4(3)(4)=16-48=-32](https://tex.z-dn.net/?f=%5Ctext%7BWe%20have%7D%5C%20a%3D3%2C%5C%20b%3D4%2C%5C%20c%3D4.%5C%5C%5C%5C%5Ctext%7BSubstitute%3A%7D%5C%5C%5C%5Cb%5E2-4ac%3D4%5E2-4%283%29%284%29%3D16-48%3D-32%3C0%5C%5C%5C%5C%5Cbold%7Bno%5C%20real%5C%20solution%7D)
X^2 and 5x both have x in common to factor out. To add or subtract them, 5x^2 is the least common denominator .
We can not really tell in this question as you dont know the equation that is being used for the domain and range relationship but overall one should know that:
The set of values of the independent variable(s) for which a function or relation is defined as the domain of a function. Typically, this is the set of x-values that give rise to real y-values.
The range of a function is the complete set of all possible resulting values of the dependent variable (y, usually), after we have substituted the domain.
Answer:
6 hours
Step-by-step explanation:
180 divided by 30 = 6
Answer:
f(-3)= - (-3)+5= +3 +5 = 8