<span>Answer:
Its too long to write here, so I will just state what I did.
I let P=(2ap,ap^2) and Q=(2aq,aq^2)
But x-coordinates of P and Q differ by (2a)
So P=(2ap,ap^2) BUT Q=(2ap - 2a, aq^2)
So Q=(2a(p-1), aq^2)
which means, 2aq = 2a(p-1)
therefore, q=p-1
then I subbed that value of q in aq^2
so Q=(2a(p-1), a(p-1)^2)
and P=(2ap,ap^2)
Using these two values, I found the midpoint which was:
M=( a(2p-1), [a(2p^2 - 2p + 1)]/2 )
then x = a(2p-1)
rearranging to make p the subject
p= (x+a)/2a</span>
Answer: 100,000 + 2000 + 200
Hope this helps!
Please mark Brainliest!
G/L=1000*g/mL, since 1 mL = 1/1000 of a litre.
<span>Therefore, 150g/L=150 000 g/mL.</span>
We need (x-h)^2 + (y-k)^2 = r^2
h = 4, k = 0 and r = 2/3
Take it from here.
It’s unsolvable with out more context. What’s the rest of the problem.
