Let's call the event of the red die to show a six as event A, and the event of the green die to show a six as event B.
The theoretical probability is defined as the ratio of the number of favourable outcomes to the number of possible outcomes. On both dices, we have 6 possible outcomes(the numbers from 1 to 6), with one favourable outcome(the number 6), therefore, the probabilities of those events are:
Each roll is independent from each other, then, the probability of both events happening simultaneously is given by their product:
Using the additive rule of probability, we have the following equation for our problem:
the probability that the red die shows a six or the green die shows a six is 11/36.
The current monthly pay can be calculated as follows;
A=p(1/r/100)^n
A=10000
r=5.9/12=0.5%
10000=p(1+0.5/100)^(4*12)
10000=p(1.005)^48
p=10000/(1.005)^48
p=7,871
the monthly payment will be:
7871/12
=$655.92
Answer: 3=-50
Step-by-step explanation:
For this case we have the following inequality:
We multiply both sides of the equation by -1.
By doing this, change the symbol of the inequality.
We have then:
From here, we clear the value of x.
We have then:
Answer:
The solution set is:
{x | x R, x < -12}
Answer:
Ay=3 over 2 or y=-2 over 3
Step-by-step explanation:
the quadratic formula: y={-b±√(b²-4ac)}/2a
In the equation 6y²-5y-6= 0, a=6, b=-5, c= -6
Substituting for the values in the formula we get:
{-(-5)±√[(-5²)-4(6)(-6)}/2(6)
{5±√169}12
={5±13}/12
(5+13)/12=3/2 or (5-13)/12= -2/3
