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marissa [1.9K]
4 years ago
12

The quartz crystal in a digital watch has a frequency of 32.8 khz. what is its period of oscillation?

Physics
1 answer:
BabaBlast [244]4 years ago
3 0
The frequency of the digital watch is:
f=32.8 kHz = 3280 Hz

The period of oscillation is equal to the reciprocal of the frequency; therefore, in this problem, the period of oscillation of the digital watch is:
T=\frac{1}{f}=\frac{1}{3280 Hz}=3.05 \cdot 10^{-4}s
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