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madam [21]
1 year ago
9

how fast would a(n) 73 kgkg man need to run in order to have the same kinetic energy as an 8.0 gg bullet fired at 430 m/sm/s ?

Physics
1 answer:
Mars2501 [29]1 year ago
8 0

Answer:

an 85 kg person run to equal the kinetic energy of an 8.0 g bullet fired at 410 m/s? The speed is, it might be argued,

v=4.0m/s

Explanation:

Typically, the mathematical formula for kinetic energy is as follows:

KE=\frac{1}{2} *m*v^{2}

K.E= kinetic energy

M=mass

V= speed

so,

KE=1/2*0.008*(420)*420

K.E=672.4J

 Therefore,

v*v=672.4/85

v*v=15.821

v=4.0m/s

Therefore

v=4.0m/s

What is Kinetic Energy?

The energy an object has as a result of motion is known as kinetic energy in physics. It is described as the effort required to move a mass-determined body from rest to the indicated velocity.

To know more about Kinetic Energy? Visit to: -

brainly.com/question/22174271

#SPJ4

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Answer:  Aerial plants is plants that lives in air or wind the wind serves as the water of the plants. Most aerial plants are found in tropical and equatorial regions of the world. In evergreen rain forests, the foliage is so thick that some plants have evolved aerial roots to allow them to absorb more sunlight. The development of aerial roots is

thus an evolutionary process.Aerial roots are often thick and spread around the parent tree. The Banyan tree can have several aerial roots as it gets older.

Explanation:

7 0
4 years ago
Calculate the electric charge of the glass ball
-Dominant- [34]

Answer:

As per Coulomb's law we know that force between two charges is given as

F = \frac{kq_1q_2}{r^2}F=

r

2

kq

1

q

2

here we know that

q_1 = 2.5 \times 10^{-6} Cq

1

=2.5×10

−6

C

q_2 = -5.0 \times 10^{-6} Cq

2

=−5.0×10

−6

C

r = 0.0050 mr=0.0050m

now from above formula we will have

F = \frac{(9 \times 10^9)(2.5 \times 10^{-6})(5 \times 10^{-6})}{(0.0050)^2}F=

(0.0050)

2

(9×10

9

)(2.5×10

−6

)(5×10

−6

)

F = 4500 NF=4500N

so they will attract towards each other as they are opposite in nature with force F = 4500 N

4 0
3 years ago
2. If an em' of Hg weighs 13.6 g, what is the mass of a cylinder of: Sem and height 20 Cm
Yuri [45]

Answer:

Let the mass of mercury  m= 13.6 gm and volume be V=1cm3.

Now change in volume when it is heated upto 50oC,

ΔV=VαΔT

ΔV=1×1.82×10−4×50

ΔV=91×10−4cm3 

New volume V1=V+ΔV=1.0091cm3

New density ρ=V1m=1.009113.6=13.48gcm−3

Explanation:

Mark me as a brainliest please

8 0
3 years ago
Butter melts when you heat it on a pan on the stove.is this a chemical changes or physical changes?
Stells [14]

Answer:

No chemical bonds are broken or formed in melting butter, so it is not a chemical change. The melting process is only a physical change, the change of state from solid to liquid.

5 0
4 years ago
Read 2 more answers
What is the final volume of a balloon that was initially 500.0 mL at 25°C and was then heated to 50°C?
horsena [70]

Answer:

V₂  =541.94 m L.

Explanation:

Given that

V₁ = 500 mL  

T₁ = 25°C  = 273 + 25 = 298 K

T₂ = 5°C = 273+50 =323  K

The final volume = V₂  

We know that ,the ideal gas equation  

If the pressure of the gas is constant ,then we can say that

\dfrac{V_2}{V_1}=\dfrac{T_2}{T_1}

\dfrac{V_2}{V_1}=\dfrac{T_2}{T_1}

Now by putting the values in the above equation we get

V_2=500\times \dfrac{323}{298}\ mL\\V_2=541.94\ mL

The final volume of the balloon will be 541.94 m L.

V₂  =541.94 m L.

4 0
3 years ago
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