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olga nikolaevna [1]

3 years ago

12

If the string is tied around your finger, when do you feel a stronger pull-when the rock is at the bottom of the swing or at the

top?

1 answer:

babymother [125]3 years ago

3 0

Bottom! I learned that the other day

You might be interested in

A massless rod is attached to the ceiling by a string. Two weights are hung from the rod: a 0.4-lb weight at its left end and a

user100 [1]

The tension in the string supporting the rod and the attached weights is 7.11 N.

<h3>Tension in the string supporting the rod</h3>

The tension in the string supporting the rod and the attached weights is the sum of the weights supported by the strings.

T = (m1 + m2)g

where;

m1 and m2 are the two masses supported

0.4lb + 1.2lb = 1.6lb = 0.725 kg

T = 0.725 x 9.8

T = 7.11 N

Learn more about tension here: brainly.com/question/918617

#SPJ1

7 0

2 years ago

A biker travels at an average speed of 18 km/hr along a 0.30 km straight segment of a bike path. How much time (in hours) does t

lawyer [7]

Answer: 0.016 h

Explanation:

$\text{Average speed} = \frac{\text {Total Distance}}{\text {total time taken}}$

It is given that, biker has an average speed = 18 km/h

Total distance traveled = 0.30 km

Therefore, time taken by biker to travel this distance:

$\Rightarrow \text{total time taken} = \frac{0.30 km}{18 km/h}=0.016 h$

Thus, the biker takes 0.016 hours to travel the segment of 0.30 km at an average speed of 18 km/h.

7 0

3 years ago

Chris and Sue are wearing harnesses and are hanging from the ceiling by means of ropes attached to them. They are face to face a

Setler [38]

Answer:

h = 0.288m

Explanation:

Assume

$v_1$ = Speed of Sue

$v_2$ = Speed of Chris immediately after the push

Sue's KE = $\frac{1}{2} mv_1\ ^2 = 26 v_1 \ ^2$

now she swings this is converted into gravitation at PE of

mg n = 52 × 9.8 × 0.65

= 331.24

$26v_{1}\ ^2$ = 331.24

So, $v_1 = 3.569$

They started at rest by conservation of momentum in case of push off the magnitude of sue momentum and it is equal to the magnitude of Chris momentum in the opposite or inverse direction

$m_1v_1 = m_2v_2$

$52 \times 3.569 = 78 \times v_2$

$v_2 = 2.380$

Chris kt = $\frac{1}{2} \times 78 \times 2.380^2$

= 220.827

220.827 = mgh

So, h = 0.288m

3 0

3 years ago

An assistant for a football team carries a 26.0 kg cooler of water from the top row of the stadium, which is a distance h = 17.5

frozen [14]

The weight of the cooler is (mg). That's (26)(9.8) = 254.8 Newtons.

Its gravitational potential energy while it's up in the top row is (mgh). That's (254.8)(17.5) = 4,459 Joules.

That's how much work it took to get the cooler up to the top row, and that's the energy it gives up when it moves back down to the bench.

In order to bring it down . . .

-- Gravity does 4,459 joules of work on the cooler.

-- The team assistant does NEGATIVE 4,459 joules of work on it.

6 0

3 years ago

What is the correct name for this formula: SiO2?

Brrunno [24]

Silicon Dioxide is the answer

6 0

4 years ago

Read 2 more answers