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a_sh-v [17]
3 years ago
14

How much force is needed to accelerate at 66 kg skier 4m/s^2 ?​

Physics
1 answer:
Ray Of Light [21]3 years ago
7 0
E force needed to accelerate a 68 kilogram-skier at a rate of
1.2
m
s
2
is 81.6 Net forces.
Explanation:
Take the mass(68kg) and the acceleration of the skier(
1.2
m
s
2
) and multiply them together
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A constant force of magnitude F acts on an object of mass 0.04kg initially at rest at a point O. If the speed of the object when
vampirchik [111]

Answer:

F = 100 Newtons

Explanation:

F = ?

m = 0.04kg

u = 0m/s ==> u is just an abbreviation for initial velocity, it is conventional.

s = 50m ==> s is just an abbreviation for distance, it is conventional.

v = 500m/s ==> v is just an abbreviation for final velocity, it is conventional.

v^{2} = u^{2} + 2as\\\\=> a = \frac{v^{2} - u^{2}}{2s}\\a = \frac{500^{2} }{2*50}\\a = 2500ms^{-2}

Then F = ma = 0.04 x 2500 = 100N

5 0
3 years ago
a bat experts a 120 N force on a 0.134 kg baseball for 0.04 seconds. what impolse is excerted on the bat
musickatia [10]
The impulse exerted by a force F on an object in a time \Delta t is given by
I = F \Delta t
In our problem, we have a force of 120 N: F=120 N, applied to the baseball for a time of \Delta t=0.04 s. Therefore the impulse is
I=F \Delta t = (120 N)(0.04 s)=4.8 Ns
3 0
3 years ago
Which statement an iron magnetic is true?
professor190 [17]
The answer is b. Please give braieies
4 0
3 years ago
100 POINTS!!! :D
charle [14.2K]

Explanation:

... in every interaction, there is a pair of forces acting on the two interacting objects. The size of the force on the first object equals the size of the force on the second object. The direction of the force on the first object is opposite to the direction of the force on the second object. Forces always come in pairs - equal and opposite action-reaction force pairs.

4 0
3 years ago
Read 2 more answers
1. A drop of oil of volume 10-10 m spreads out on water to
ankoles [38]

Answer:

318.3 nm

Explanation:

We approximate the circular film as a cylinder of height h and radius, r. Its volume V = πr²h. Since this volume equals the volume of the oil drop, the height of the circular film is thus h = V/πr²

V = 10⁻¹⁰ m³ and r = 10 m

Substituting into h, we have

h = 10⁻¹⁰ m³/π(10)²

= 0.3183 × 10⁻¹² m

= 3183 × 10⁻⁹ m

= 318.3 nm

5 0
3 years ago
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