First, convert 2.0 mL of AlCl3 to grams using the density, which is 2.48g/mL. So 2.48g/mL * 2.0 mL = 4.96g. Then find the molar mass of aluminum chloride and divide 4.96 by this number, which is 133.34g. 4.96g*(1mol/133.34g) = .0372 mols AlCl3. Check for significant digits though.
CaCl2
All of the other choices are elements
Answer:
cis-hex-2-ene as produced as major product.
Explanation:
- In presence of (Lindlar catalyst) and , alkynes are reduced to alkene.
- molecules first adsorbed onto metal surface through chemisorption.
- When alkyne molecule comes in close proximity to the metal surface, H atoms add onto triple bond to reduce it to alkene.
- Two H atoms add onto alkyne from same face of metal. So, (Z) or cis-isomer of alkene is produced as a major product.
- Reaction mechanism has been shown below.
Answer:
starch.........................