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iren [92.7K]
3 years ago
11

Use the information from the graph to answer the question. A graph titled Velocity versus Time shows time in seconds on the x ax

is, numbered 0 to 25, velocity in meters per second on the y axis, numbered 0 to 40. A line starts at (0, 10) and ends at (25, 35). What is the total displacement of the object? m
Physics
2 answers:
Ivahew [28]3 years ago
7 0

the answer is 562.5m

jarptica [38.1K]3 years ago
4 0

Answer:

its -2.5 on edge 2020

Explanation:

i just took the quiz answer above is the next part of the quiz, answer is 562.5

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Question 1 This is slowing the flow of electrons (the current) and where some of the electrons' energy gets converted into heat.
shepuryov [24]

Answer:

conductor

Explanation:

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2 years ago
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How old is a bone if it still has 50% of its carbon-14 content?
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Answer:

5730 years

Explanation:

The half life of carbon-14 is 5730 years.  If 50% of the carbon-14 remains, then exactly 1 half life has passed.

The half-life equation is:

A = A₀ (½)^(t / T)

where A is the remaining amount,

A₀ is the initial amount,

t is time,

and T is the half life.

In this case, A = ½ A₀ and T = 5730.

½ A₀ = A₀ (½)^(t / 5730)

½ = (½)^(t / 5730)

1 = t / 5730

t = 5730

6 0
2 years ago
Mrs. Davis has asked Kyle to retrieve the compound mixture from the chemical cabinet. Which of the following should Kyle retriev
nignag [31]

Answer:

water

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3 0
3 years ago
A positive charge of 18nC is evenly distributed along a straight rod of length 4.0 m that is bent into a circular arc with a rad
sergey [27]

Explanation:

Formula for angle subtended at the center of the circular arc is as follows.

           \theta = \frac{S}{r}

where,   S = length of the rod

              r = radius

Putting the given values into the above formula as follows.      

                \theta = \frac{S}{r}

                             = \frac{4}{2}

                             = 2 radians (\frac{180^{o}}{\pi})

                             = 114.64^{o}

Now, we will calculate the charge density as follows.

                 \lambda = \frac{Q}{L}

                            = \frac{18 \times 10^{-9} C}{4 m}

                            = 4.5 \times 10^{-9} C/m

Now, at the center of arc we will calculate the electric field as follows.

                 E = \frac{2k \lambda Sin (\frac{\theta}{2})}{r}

                     = \frac{2(9 \times 10^{9} Nm^{2}/C^{2})(4.5 \times 10^{-9}) Sin (\frac{114.64^{o}}{2})}{2 m}

                      = 34.08 N/C

Thus, we can conclude that the magnitude of the electric eld at the center of curvature of the arc is 34.08 N/C.

5 0
3 years ago
Subduction occurs at which of the following tectonic plate boundaries?
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When two tectonic plates collide and form a converging plate boundry, normally one of the plates will slide underneath the other and that is when Subduction occurs.
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