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mr_godi [17]
2 years ago
9

Which one will it be

Physics
2 answers:
liq [111]2 years ago
3 0

Answer:

none

Explanation:

it's to high up to be affected by the gravity

Airida [17]2 years ago
3 0
A)Zero
that is the right answer
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If the lily pads are spaced 2.4 m apart and Ferdinand jumps with a speed of 5 m/s taking 0.6 s to go from lily pad to lily pad,
Zina [86]

Answer:

36.87^{\circ}

Explanation:

v = Velocity of Ferdinand = 5 m/s

\theta = Angle of jump

T = Time taken = 0.6 s

R = Distance between lily pads = 2.4 m

Horizontal range is given by

R=v_xT\\\Rightarrow R=vcos\theta T\\\Rightarrow cos\theta=\dfrac{R}{vT}\\\Rightarrow \theta=cos^{-1}\dfrac{R}{vT}\\\Rightarrow \theta=cos^{-1}\dfrac{2.4}{5\times 0.6}\\\Rightarrow \theta=36.87^{\circ}

The angle at which Ferdinand make each of his jumps is 36.87^{\circ}

8 0
3 years ago
Calculate the intensity of current flowing through a computer that consumes 180W and operates at 120 V.
padilas [110]

Answer:

C) 1.5 A

Explanation:

P = IV

180 W = I (120 V)

I = 1.5 A

5 0
3 years ago
Each corner of a right-angled triangle is occupied by identical point charges "A", "B", and "C" respectively. Draw a sketch of t
NISA [10]

Answer:

Fnet = F√2

Fnet = kq²/r² √2

Explanation:

A exerts a force F on B, and C exerts an equal force F on B perpendicular to that.  The net force can be found with Pythagorean theorem:

Fnet = √(F² + F²)

Fnet = F√2

The force between two charges particles is:

F = k q₁ q₂ / r²

where

k is Coulomb's constant, q₁ and q₂ are the charges, and r is the distance between the charges.

If we say the charge of each particle is q, then:

F = kq²/r²

Substituting:

Fnet = kq²/r² √2

5 0
3 years ago
Help Please!!!!!!!!!!!!!!!!!!
julia-pushkina [17]
The answer is 59.4 degrees.
4 0
3 years ago
Which of the following would be useful to show the growth rate of plants at verying temperatures?
astraxan [27]
B or d most likely, because a frequency table you can show for example the amount of time the plant grew to 30 cm in 87 degree feirenhieght 
3 0
3 years ago
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