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adell [148]
3 years ago
12

A 6 m long rope is stretched between two supports with a tension that makes the speed of transverse waves 120 m/s. What is the w

avelength of the fourth harmonic?
a. 3m

b. 6m

c. 12m

d. 40m
Physics
1 answer:
Alexxx [7]3 years ago
3 0

If rope is given in fourth harmonic

then it means that rope will have FOUR loops

One loop is always length of half wavelength

SO total length of the rope is given as

L = n\frac{\lambda}{2}

now here we know

L = 6 m

n = Fourth Harmonic

6 = 4 * \frac{\lambda}{2}

now we have

\lambda = 3 m

so option A is correct

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maxonik [38]
I’m not sure with the question
4 0
3 years ago
A block of mass m moving due east at speed v collides with and sticks to a block of mass 2m that is moving at the same speed vv
lapo4ka [179]

Answer:

30.36°

Explanation:

By using linear momentum; linear momentum can be expressed by the relation:

mv_xi + mv_yj

where ;

m= mass

v_x = velocity of components in the x direction

v_y = velocity of components in the y direction

If we consider the east as the positive x and north as positive y which is synonymous to what we usually have on a graph.

Then;

Initial momentum = mvi + 2mvcos 45i + 2mvsin45 j

= (mv+2mvcos45)i + (2mvsin45)j

However, the masses stick together after collision and move with a common velocity: V_xi +V_yj

∴ Final momentum = 3mv (V_xi +V_yj)

= 3mV_xi + 3mV_yj

From the foregoing ;

initial momentum = final momentum

3mV_xi + 3mV_yj = (mv+2mvcos45)i+(2mvsin45j)

So;

3mV_x = mv + 2mv cos 45 \\\\3mV_y = 2mV sin 45

V_x = \frac{mv+2mvcos45 }{3m}\\\\V_x = \frac{v+2vcos45}{3}

V_y = \frac{2mvsin45}{3m} \\\\V_y = \frac{2vsin45}{3}

Finally;

The required angle θ = tan^{-1} = \frac{V_y}{V_x}

θ = tan^{-1} = \frac{\frac{2vsin45}{3}}{\frac{v+2v.cos45}{3}}

θ = tan^{-1} = \frac{2sin 45}{1+2cos45}\\\\

θ = 30.36°

7 0
3 years ago
How many seconds did it take (after starting his descent) for the worker to hit the ground? Answer in units of s.
elena-14-01-66 [18.8K]

Answer:

This question is incomplete

Explanation:

The question is incomplete. However, to determine the time (in seconds) it took a worker to hit the ground from an elevated point. The speed the worker was coming with to the ground and the distance between the elevated point and the ground will have to be considered. Thus the formula to be used here will be

Speed (in meter per second) = distance (in meters) ÷ time (in seconds)

time (in seconds) = distance (in meters) ÷ speed (in meter per seconds)

6 0
3 years ago
When does resonance occur?
bija089 [108]
Resonance occurs<span> when the amplitude of an object's oscillations are increased by the matching vibrations of another object.

Source: </span>Resonance: Definition & Transmission of Waves
4 0
4 years ago
Read 2 more answers
A ball with a mass of 2.89 kg bounces off of the ground. Just before it hits the ground, its velocity is 6.00 m/s in the downwar
White raven [17]

Answer:

30.46 kgm/s

Explanation:

According to conservation law of momentum, the magnitude of the impulse J that the ground gave the ball equals to the change in momentum of the ball before and after it hits the ground.

Before the hit, the ball velocity is 6m/s, so its momentum is 6 * 2.89 = 17.34 kgm/s

After the hit, the ball velocity is -4.54 m/s in the opposite direction, so its momentum is 2.89*(-4.54) = -13.12 kgm/s

So the change of momentum, and also the impulse is

17.34 - (-13.12) = 30.46 kgm/s

3 0
3 years ago
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