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Llana [10]
3 years ago
5

An astronaut is in equilibrium when he is positioned 140 km from the center of asteroid C and 581 km from the center of asteroid

Y, along the straight line joining the centers of the asteroids. What is the ratio of the masses X/Y of the asteroids?A. 17.2B. 0.0581C. 0.241D. 4.15
Physics
1 answer:
serg [7]3 years ago
8 0

Answer:B

Explanation:

Given

Distance of astronaut From asteroid x is r_x=140 km

Distance of astronaut From asteroid Y is r_y=581 km

Suppose M,M_x,M_y be the masses of Astronaut , asteroid X and Y

If the astronaut is in equilibrium then net gravitational force on it is zero

F_x=F_y

\frac{GMM_x}{r_x^2}=\frac{GMM_y}{r_y^2}

cancel out the common terms we get

\frac{M_x}{r_x^2}=\frac{M_y}{r_y^2}

\frac{M_x}{M_y}=(\frac{r_x}{r_y})^2

\frac{M_x}{M_y}=(\frac{140}{581})^2

\frac{M_x}{M_y}=0.05806\approx 0.0581

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Answer:

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2). Toward us

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4). Toward us

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Spectral lines will be shifted to the blue part of the spectrum if the source of the observed light is moving toward the observer, or to the red part of the spectrum when it is moving away from the observer (that is known as the Doppler effect).

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Blueshift: 121.4nm < 121.6nm

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Due to that shift the velocity of the star can be determine by means of Doppler velocity.

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<em>Case for star 1 \lambda_{measured} = 120.4 nm:</em>

<em></em>

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Notice that the negative velocity means that is approaching to the observer.

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v = (3x10^{8}m/s)(\frac{121.4nm-121.6nm}{121.6nm})

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Answer:

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