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vovikov84 [41]
3 years ago
15

Light____.

Physics
2 answers:
ycow [4]3 years ago
5 0

Answer:

b

Explanation:

light does not need a medium

it is refracted

Light is made up of little packets of energy called photons.

electromagnetic waves

Darya [45]3 years ago
5 0

Answer:

b

Explanation:

trust me :)

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What does it mean if the moon is waxing and waning
konstantin123 [22]
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Taya2010 [7]

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4 0
3 years ago
Read 2 more answers
Over an interval of 4.0 s the average rate of change of the concentration of B was measured to be -0.0760 M/s. What is the final
Serhud [2]

Complete question:

Consider the hypothetical reaction 4A + 2B → C + 3D

Over an interval of 4.0 s the average rate of change of the concentration of B was measured to be -0.0760 M/s. What is the final concentration of A at the end of this same interval if its concentration was initially 1.600 M?

Answer:

the final concentration of A is 0.992 M.

Explanation:

Given;

time of reaction, t = 4.0 s

rate of change of the concentration of B =  -0.0760 M/s

initial concentration of A = 1.600 M

⇒Determine the rate of change of the concentration of A.

From the given reaction: 4A + 2B → C + 3D

2 moles of B ---------------> 4 moles of A

-0.0760 M/s of B -----------> x

x = \frac{4(-0.076)}{2} \\\\x = -0.152 \ M/s

⇒Determine the change in concentration of A after 4s;

ΔA = -0.152 M/s  x 4s

ΔA = -0.608 M

⇒ Determine the final concentration of A  after 4s

A = A₀ + ΔA

A = 1.6 M + (-0.608 M)

A = 1.6 M - 0.608 M

A = 0.992 M

Therefore, the final concentration of A is 0.992 M.

5 0
2 years ago
Kinetic energy varies jointly as the mass and the square of the velocity. A mass of 1515 grams and velocity of 77 centimeters pe
Alexus [3.1K]

Answer:

The second kinetic energy is 162 J.

Explanation:

Given that,

Mass, m_1=15\ g

Velocity, v_1=7\ cm/s

Kinetic energy, K_1=147\ ergs

Mass, m_2=10\ g

Velocity, v_2=9\ cm/s

We need to find kinetic energy K_2. Kinetic energy is given by :

K=\dfrac{1}{2}mv^2

So,

\dfrac{K_1}{K_2}=\dfrac{m_1}{m_2}\times \dfrac{v_1^2}{v_2^2}\\\\K_2=\dfrac{K_1}{\dfrac{m_1}{m_2}\times \dfrac{v_1^2}{v_2^2}}\\\\K_2=\dfrac{147}{\dfrac{15}{10}\times \dfrac{7^2}{9^2}}\\\\K_2=162\ J

So, the second kinetic energy is 162 J.

4 0
3 years ago
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