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vovikov84 [41]
3 years ago
15

Light____.

Physics
2 answers:
ycow [4]3 years ago
5 0

Answer:

b

Explanation:

light does not need a medium

it is refracted

Light is made up of little packets of energy called photons.

electromagnetic waves

Darya [45]3 years ago
5 0

Answer:

b

Explanation:

trust me :)

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How does a generator produce electrical energy?
Daniel [21]
The correct answer is B. it converts mechanical energy to electrical energy.
3 0
3 years ago
Read 2 more answers
Amazon rectangular bar of low carbon steel A-36 is exposed to an axial strees of 150 MPa. What is the original length of the bar
kolbaska11 [484]

Answer:

1.8m

Explanation:

Let the Elastics of the steel ASTM-36 E = 200000 MPa

The strain of the bar when subjected to 150 MPa is

\epsilon = \frac{\sigma}{E} = \frac{150}{200000} = 0.00075

Therefore, if the bar elongates by 1.35 mm, then the original length L would be:

\epsilon = \frac{\Delta L}{L}

L = \frac{\Delta L}{\epsilon} = \frac{1.35}{0.00075} = 1800 mm or 1.8m

5 0
3 years ago
What is the mass of a rock lifted 2 meters off the ground that has 196 J of potential energy?
eimsori [14]

Answer:

10kg

Explanation:

Let PE=potential energy

PE=196J

g(gravitational force)=9.8m/s^2

h(change in height)=2m

m=?

PE=m*g*(change in h)

196=m*9.8*2

m=10kg

4 0
3 years ago
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!! I CANNOT RETAKE THIS AND I NEED ALL CORRECT ANSWERS ONLY!!!
valentinak56 [21]

Answer:

Electric Current

Explanation:

The flow (or free movement) of these electrons through a wire.

Pretty sure :)

6 0
3 years ago
Read 2 more answers
Space-shuttle astronauts experience accelerations of about 35 m/s2 during takeoff. What force does a 75 kg astronaut experience
amm1812

Answer:

<h3>The answer is 2625 N</h3>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 75 × 35

We have the final answer as

<h3>2625 N</h3>

Hope this helps you

5 0
3 years ago
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