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Mama L [17]
2 years ago
7

A sports car and a minivan run out of gas and are pushed to the side of the road. Which is easier to push, and why?

Physics
2 answers:
Olin [163]2 years ago
4 0

Answer: d

Explanation:

Setler [38]2 years ago
4 0

Answer:

the last one

Explanation:

Just took the test

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In one of the classic nuclear physics experiments at the beginning of the 20th century, an alpha particle was accelerated toward
BaLLatris [955]

Answer:

= 4.3 × 10 ⁻¹⁴ m

Explanation:

The alpha particle will be deflected when its kinetic energy is equal to the potential energy

Charge of the alpha particle q₁= 2 × 1.6 × 10⁻¹⁹ C = 3.2 × 10⁻¹⁹ C

Charge of the gold nucleus q₂= 79 × 1.6 × 10⁻¹⁹ = 1.264 × 10⁻¹⁷C

Kinetic energy of  the alpha particle = 5.28 × 10⁶ × 1.602 × 10⁻¹⁹ J ( 1 eV)

=  8.459 × 10⁻¹³

k electrostatic force constant = 9 × 10⁹ N.m²/c²

Kinetic energy = potential energy =   k q₁q₂ / r where r is the closest distance the alpha particle got to the gold nucleus

r = (  9 × 10⁹ N.m²/c² × 3.2 × 10⁻¹⁹ C × 1.264 × 10⁻¹⁷C) / 8.459 × 10⁻¹³

= 4.3 × 10 ⁻¹⁴ m

3 0
3 years ago
You are traveling at 100 km/hr to make it to work on time. You have to be to work in .25 hr or you will be late. You have 16 km
alexgriva [62]

Answer: Yes

Explanation:

Velocity V is defined as the distance traveled d in a specific time t:

V=\frac{d}{t}

If you are traveling at V=100 km/h a distance d=16 m, then the time it will take you to be at work is:

t=\frac{d}{V}=\frac{16 km}{100 km/h}

t=0.16 h

This means you will make it on time, because this time is less than 0.25 h.

4 0
3 years ago
if the amplitude of sine curve is 4 and the frequency is 1 with no phase shift, what is the function that descirbes this curve?
Vlada [557]

Answer:

y = 4 Sin (2πt)

Explanation:

Amplitude, A = 4

frequency, f = 1

Wave function is given by

y = A sinωt

where, ω is angular frequency

ω = 2 π f = 2 π x 1 = 2π

So, the desired wave function

y = 4 Sin (2πt)

8 0
3 years ago
If the airman had a mass of 80 kg, find the magnitude of the air drag acting on him when he reached terminal velocity of 54 m/s
Vlad1618 [11]

The magnitude of the air drag is 784 N

Explanation:

An object falling down reaches the terminal velocity when the magnitude of the air drag acting on it becomes equal to the weight of the object. Mathematically, this condition can be written as:

F_D = mg

where

F_D is the magnitude of the air drag

m is the mass of the object

g is the acceleration of gravity

In this problem, we have

m = 80 kg is the mass of the airman

g=9.8 m/s^2 is the acceleration of gravity

Substituting into the formula, we find:

F_D = (80)(9.8)=784 N

Learn more about forces here:

brainly.com/question/8459017

brainly.com/question/11292757

brainly.com/question/12978926

#LearnwithBrainly

4 0
2 years ago
A box weighing 10 N is 4 m away from the fulcrum. How much force must be applied 1 m away on the opposite end of the fulcrum in
julia-pushkina [17]

Answer: Socratic

Explanation: i’m not sure but you can use Socratic it’s a good app that helps

4 0
3 years ago
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