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3 years ago

A sports car and a minivan run out of gas and are pushed to the side of the road. Which is easier to push, and why?

Physics

2 answers:

Olin [163]3 years ago

4 0

Answer: d

Explanation:

Setler [38]3 years ago

4 0

Answer:

the last one

Explanation:

Just took the test

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A second rock is thrown straight upward with a speed 4.750 m/s . If this rock takes 2.006 s to fall to the ground, from what hei

Naddika [18.5K]

Answer:

29.23 meters

Explanation:

H = ut + 1/2gt^2

Initial velocity u = 4.750m/s

time t = 2.006 secs

Acceleration due to gravity g = 9.8m/s^2

H =

4.750 x 2.006 + 1/2 x 9.8 x (2.006)^2

9.53 + 1/2 x 9.8 x 4.02

9.53 + 39.396/2

9.53 + 19.698

29.23 meters

8 0

3 years ago

Sebuah pegas memiliki beban 5 kg dan digantung vertikal. Jika pegas tersebut bertambah panjang 7 cm maka perubahan energi potens

professor190 [17]

Answer:

It is elastic potential energy

Explanation:

Elastic potential energy is stored energy that results from applying a force to deform an elastic object. The energy is stored until the force is removed and the elastic object returns to its original shape, doing work in the process. Deformation may involve compressing, stretching, or twisting the object. Many objects are specifically designed to store elastic potential energy, for example:

The spring of a winding watch.

5 0

3 years ago

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A 0.0400-g positive charged ball with charge q = 6.40 μC is resting on a flat, frictionless horizontal surface. For a time of t

Leto [7]

Answer:

The height is 0.1014 m

Explanation:

Given that,

Mass = 0.0400 g

Charge $q= 6.40\ \mu C$

Time t = 0.0420 s

Electric field $E=7.80\times10^{2}\ N/C$

We need to calculate the electric force on the particle

Using formula of electric force

$F=qE$

Put the value into the formula

$F_{e}=6.40\times10^{-6}\times7.80\times10^{2}$

$F_{e}=0.004992= 0.499\times10^{-2}\ N$

We need to calculate the gravitational force

Using formula of force

$F=mg$

Put the value into the formula

$F_{g}=0.0400\times10^{-3}\times9.8$

$F_{g}=0.000392 = 0.392\times10^{-3}\ N$

We need to calculate the net force

$F_{net}=F_{e}-F_{g}$

$F_{net}=0.499\times10^{-2}-0.392\times10^{-3}$

$F_{net}=0.004598= 0.4598\times10^{-2}\ N$

We need to calculate the acceleration

Using newton's law

$F = ma$

$a = \dfrac{F}{m}$

$a=\dfrac{0.4598\times10^{-2}}{0.0400\times10^{-3}}$

$a =114.95\ m/s^2$

We need to calculate the height

Using equation of motion

$s = ut+\dfrac{1}{2}at^2$

$s=0+\dfrac{1}{2}\times114.95\times(0.0420)^2$

$s=0.1014\ m$

Hence, The height is 0.1014 m

3 0

3 years ago

Astronomers estimate that a galaxy contains a. 100 stars. c. millions or billions of stars. b. 1 star. d. 100,000 stars.

In-s [12.5K]

C.

Galaxies are very big, with millions or billions of stars in them.

Hope this helps!

3 0

3 years ago

Define First Condition of Equilibrium ??

spayn [35]

Answer:

First Condition of Equilibrium is that it must be experiencing no acceleration or the external forces acting on the body should be zero.

7 0

2 years ago

Read 2 more answers