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3 years ago

A banked circular highway is designed for traffic moving

Physics

1 answer:

Nuetrik [128]3 years ago

3 0

Answer:

0.063

Explanation:

velocity of the car, v = 40 km/h = 11.11 m/s

radius, r = 200 m

Let the coefficient of friction is μ.

The coefficient of friction relates to the velocity on banked road is given by

$\mu =\frac{v^{2}}{rg}$

where, v is the velocity, r be the radius of the curve road and μ is coefficient of friction.

By substituting the values, we get

$\mu =\frac{11.11^{2}}{200\times 9.8}$

μ = 0.063

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Assume that the speed of light in a vacuum has the hypothetical value of 18.0 m/s. A car is moving at a constant speed of 14.0 m

Oksi-84 [34.3K]

Answer:

Observed time, t = 5.58 s

Explanation:

Given that,

Speed of light in a vacuum has the hypothetical value of, c = 18 m/s

Speed of car, v = 14 m/s along a straight road.

A home owner sitting on his porch sees the car pass between two telephone poles in 8.89 s.

We need to find the time the driver of the car measure for his trip between the poles. The relation between real and observed time is given by :

$T=\dfrac{t}{\sqrt{1-\dfrac{v^2}{c^2}} }$

t is observed time.

$t=T\times \sqrt{1-\dfrac{v^2}{c^2}} \\\\t=8.89\times \sqrt{1-\dfrac{14^2}{18^2}} \\\\t=5.58\ s$

So, the time observed by the driver of the car measure for his trip between the poles is 5.58 seconds.

4 0

3 years ago

If the density of a diamond is 3.5 g/cm", what would be the mass of a diamond whose

alexandr1967 [171]

Answer:

Explanation:

7 0

3 years ago

1. On one of the shelves in your physics lab is displayed an antique telescope. A sign underneath the instrument says that the t

Ira Lisetskai [31]

Answer:

a) $f_{e}$ = 3,375 cm , b) f₀ = 77.625 cm

Explanation:

The magnification of a telescope is, to see at the far point of vision (infinity image)

m = - f₀ / $f_{e}$

The length of the tube is

L = f₀ + $f_{e}$

a) The focal length of the eyepiece

L = - m $f_{e}$ + $f_{e}$

L = $f_{e}$ (1-m)

$f_{e}$ = L / (1-m)

Let's calculate

$f_{e}$ = 81.0 / (1 - (-23.0)

$f_{e}$ = 3,375 cm

b) the focal length of the target

f₀ = -m $f_{e}$

f₀ = 23 (3.68)

f₀ = 77.625 cm

8 0

3 years ago

Question 1:

german

Answer:

well I done really know ask the others person

7 0

2 years ago

Use the slit example to explain why you can hear a noise in another room through an open door.

defon

Because the wall reflects sound waves to your ears bouncing off of the walls, even if it's in another room.

8 0

3 years ago