Answer:
See proof below
Step-by-step explanation:
An equivalence relation R satisfies
- Reflexivity: for all x on the underlying set in which R is defined, (x,x)∈R, or xRx.
- Symmetry: For all x,y, if xRy then yRx.
- Transitivity: For all x,y,z, If xRy and yRz then xRz.
Let's check these properties: Let x,y,z be bit strings of length three or more
The first 3 bits of x are, of course, the same 3 bits of x, hence xRx.
If xRy, then then the 1st, 2nd and 3rd bits of x are the 1st, 2nd and 3rd bits of y respectively. Then y agrees with x on its first third bits (by symmetry of equality), hence yRx.
If xRy and yRz, x agrees with y on its first 3 bits and y agrees with z in its first 3 bits. Therefore x agrees with z in its first 3 bits (by transitivity of equality), hence xRz.
Answer:
y^3/(27 x^3)
Step-by-step explanation:
Simplify the following:
((3 x)/y)^(-3)
((3 x)/y)^(-3) = (y/(3 x))^3:
(y/(3 x))^3
Multiply each exponent in y/(3 x) by 3:
(y^3)/((3 x)^3)
Multiply each exponent in 3 x by 3:
y^3/(3^3 x^3)
3^3 = 3×3^2:
y^3/(3×3^2 x^3)
3^2 = 9:
y^3/(3×9 x^3)
3×9 = 27:
Answer: y^3/(27 x^3)
When given the points (x1,y1) and (x2,y2)
slope=(y2-y1)/(x2-x1)
we have
(3,0) and (3,-2)
(x,y)
x1=3
y1=0
x2=3
y2=-2
slope=(-2-0)/(3-3)=-2/0=undefined since you caon't divide by zero
answer is D
Answer:
7/15 is your answer
Step-by-step explanation:
explanation
3x(5+x) - 2x(3x-7)
open the brackets, we have
15x + 3x^2 - 6x^2 + 14x
collect like terms
3x^2 - 6x^2 +15x + 14x
-3x^2 + 29x
answer= -3x^2 + 29x
