3 years ago

Find the 14th term of the geometric sequence 7, 28, 112,

Mathematics

1 answer:

Fed [463]3 years ago

6 0

Answer:

a(14)=469762048

Step-by-step explanation:

geometric sequence= a(n)=a*r^(n-1)

we have:

a=7

r=28/7=4

So:

a(14)=7*4^(14-1)

=7*4^(13)

=469762048

hope this helps

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Jayden evaluated the expression a ÷ (2 + 1.5) for a = 14. He said that the value of the expression was 8.5. Select all the state

Darina [25.2K]

Answer:

C) Jayden divided 14 by 2 and then added 1.5.

Step-by-step explanation:

Jayden did

(14/2)+1.5 which is 8.5

so C is correct.

Hope this helps plz hit the crown :D

6 0

3 years ago

a toy rocket is launched from the top of a 48 foot hill. The rockets initial upward velocity is 32 feet per second and its heigh

sdas [7]

Answer:

t = 2.11 seconds

Step-by-step explanation:

A toy rocket is launched from the top of a 48 foot hill. The rockets initial upward velocity is 32 feet per second and its height h at any given second t is modeled by the equation:

$h=-16t^2+32t+48$

Let us assume that we need to find the time by it to reach the ground. It means h = 0

$-16t^2+32t+48=0$

The above is a quadratic equation. The value of t is given by :

$t=\dfrac{-b\pm \sqrt{b^2-2ac} }{2a}\\\\t=\dfrac{-b+ \sqrt{b^2-2ac} }{2a},\dfrac{-b- \sqrt{b^2-2ac} }{2a}\\\\t=\dfrac{-32+ \sqrt{(32)^2-2\times (-16)(8)} }{2\times (-16)},\dfrac{-32-\sqrt{(32)^{2}-2\times(-16)(8)}}{2\times(-16)}\\\\t=-0.11\ s, 2.11\ s$