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3 years ago

1. Using Pj= e^-BE/Z in the Gibb’s form for

Physics

1 answer:

Effectus [21]3 years ago

3 0

Answer:

Explanation:

Solution. The Gibbs formula for the entropy is

S = −KB∑pi ㏑(pi).

Using the Boltzmann probability in the canonical ensemble pi = exp(−βEi)/Z, we have,

S = −kB∑ pi[ -(Ei ÷ KBT) - ㏑(Z)] = (U÷T)+ kBln(Z) so U − T S = −kBTln(Z),

where we used∑ P i = 1 , U= ∑i piEi

You might be interested in

The barrier to C-C bond rotation in iodoethane is 13 kJ/mol. What energy can you assign to an H-I eclipsing interaction?

n200080 [17]

Answer:

5J/mol

Explanation:

H-H eclipsed = Torsional strain = 4.0 kJ/mol

H-CH3 eclipsed = Mostly torsional strain = 6.0 kJ/mol

CH3-CH3 eclipsed =Torsional and steric strain = 11.0 kJ/mol

CH3-CH3 gauche = Steric strain = 3.8 kJ/mol

You know each H-H eclipsed is 4 kJ/mol (8 kJ/mol total) and the reported barrier is 13 kJ/mol. Therefore the H-I eclipsed interaction must be 5 kJ/mol, (13-8 = 5).

7 0

3 years ago

The length of the adult mosquito is typically between 3.0 mm and 6.0 mm. The smallest known mosquitoes are around 2.5 mm, and th

FrozenT [24]

0.74in

Explanation:

Given parameters:

length range of adult mosquito = 3.0 - 6.0mm

Smallest mosquito = 2.5mm

Largest mosquito = 19mm

Average mass range = 3.0 - 5.0mg

Unknown:

Length of largest known mosquito in inches = ?

Solution;

The length is the longest dimension. It is how long a body is.

The problem here is converting from mm to inches;

The length of the longest mosquito which is the largest is 19mm

19mm to inches;

1mm = 0.039inches

19mm = 19mm x $\frac{0.039in}{1mm}$ = 0.74in

learn more:

Scale brainly.com/question/570757

#learnwithBrainly

4 0

3 years ago

Ideal gases are often studied at standard ambient temperature and pressure (satp). The international union of pure and applied c

11Alexandr11 [23.1K]

This problem provides information about the pressure and temperature ideal gases are studied at. The answer to the questions are that all molecules have the same density, 2.43x10²⁵ mol/m³ and 2.43x10¹⁹ mol/cm³.

<h3>Idela gases</h3>

In science, we can start studying gases with the concept of ideal gas, as they do not collide one to another and are assumed to be perfect spheres with no relevant interactions.

In such a way, one can conclude that the <u>number density of all ideal gasses at SATP is the same</u>, as they are assumed to be perfect spheres with equal volumes per molecule.

Moreover, when calculating the number of molecules per cubic meter, one must use the ideal gas equation as:

$PV=nRT\\\\\frac{N}{V}= \frac{P*N_A}{RT}$

And plug in the numbers we are given:

$\frac{N}{V}= \frac{100kPa*\frac{1000Pa}{1kPa}*6.022x10^{23}molec/mol}{8.314\frac{Pa*m^3}{mol*K}*298K}=2.43x10^{25}molec/m^3$

Lastly, we can calculate the molecules per cubic centimeter by performing the following conversion:

$2.43x10^{25}\frac{molec}{m^3}*(\frac{1m}{100cm} )^3\\ \\=2.43x10^{19}\frac{molec}{cm^3}$

Learn more about ideal gases: brainly.com/question/26450101

5 0

3 years ago

The most recently discovered system close to Earth is a pair of brown dwarfs known as Luhman 16. It has a distance of 6.5 light-

just olya [345]

Answer:

1.99 parsecs.

Explanation:

We have been given that the most recently discovered system close to Earth is a pair of brown dwarfs known as Luhman 16. It has a distance of 6.5 light-years.

We know that one light year equals to 0.306601 parsecs. To convert 6.5 light-years to parsecs, we will multiply 0.306601 by 6.5.

$6.5\text{ Light-years}=6.5\times 0.306601\text{ Parsecs}$