A proton is confined within an atomic nucleus of diameter 3.60 fm. part a estimate the smallest range of speeds you might find f
1 answer:
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Answer:
B. About 12 degrees
Explanation:
The orbital period is calculated using the following expression:
T = 2π*()
Where r is the distance of the planet to the sun, G is the gravitational constant and m is the mass of the sun.
Now, we don't actually need to solve the values of the constants, since we now that the distance from the sun to Saturn is 10 times the distance from the sun to the earth. We now this because 1 AU is the distance from the earth to the sun.
Now, we divide the expression used to calculate the orbital period of Saturn by the expression used to calculate the orbital period of the earth. Notice that the constants will cancel and we will get the rate of orbital periods in terms of the distances to the sun:
=
Knowing that the orbital period of the earth is 1 year, the orbital period of Saturn will be years, or 31.62 years.
We find the amount of degrees it moves in 1 year:
or about 12 degrees.
Answer:
a)
b) the motorcycle travels 155 m
Explanation:
Let , then consider the equation of motion for the motorcycle (accelerated) and for the car (non accelerated):
where:
is the speed of the motorcycle at time 2
is the velocity of the car (constant)
is the velocity of the car and the motorcycle at time 1
d is the distance between the car and the motorcycle at time 1
x is the distance traveled by the car between time 1 and time 2
Solving the system of equations:
For the second part, we need to calculate x+d, so you can use the equation of the car to calculate x: