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lina2011 [118]
3 years ago
12

Who developed the steady-state hypothesis for the universe? When was it developed?

Physics
2 answers:
Gnoma [55]3 years ago
6 0

Answer:

The steady-state theory was first proposed by Sir James Jeans in the 1920s, but it really got a boost in 1948 when it was reformulated by Fred Hoyle, Thomas Gold, and Hermann Bondi.

Explanation:

True

Alex17521 [72]3 years ago
4 0

Answer:

The steady-state theory was first proposed by Sir James Jeans in the 1920s, but it really got a boost in 1948 when it was reformulated by Fred Hoyle, Thomas Gold, and Hermann Bondi.

Explanation:

The steady-state theory was first proposed by Sir James Jeans in the 1920s, but it really got a boost in 1948 when it was reformulated by Fred Hoyle, Thomas Gold, and Hermann Bondi.

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The pressure of the earth's atmosphere at sea level is 14.7 lb/in2. What is the pressure when expressed in g/m2? (2.54 cm = 1 in
miss Akunina [59]
<h2>Answer:</h2>

14.7 lb / in² = 10333018.166 g / m²

<h2>Explanation:</h2>

Given from the question;

pressure = 14.7lb/in²

<u>To convert from lb / in² to g / m²</u>

Note;

2.54 cm = 1 in       ------------(i)

But;

100 cm = 1m

=> 2.54cm = 2.54 cm x 1 m / 100 cm = 0.0254m

=>2.54cm = 0.0254m

Substitute 2.54cm = 0.0254m into equation(i)

=> 0.0254m = 1 in

<em>Note also;</em>

2.205 lb = 1 kg            ------------------(ii)

But;

1kg = 1000g

Substitute 1kg = 1000g into equation (ii)

=> 2.205 lb = 1000g   ---------------------(iii)

<em>From equation(iii);</em>

if, 2.205 lb = 1000g

then, 1 lb = 1 lb x 1000 g / 2.205 lb = 453.5g

=> 1 lb = 453.5 g

<em>Now let's convert 14.7 lb/in² to g / m²;</em>

=> 14.7 lb / in² could be written as 14.7 x 1 lb / (1 in x 1 in)

i.e

=> 14.7 lb / in² = 14.7 x 1 lb / (1 in x 1 in)     ------------------(iv)

<em>Substitute the values of 1 lb = 453.5g and 1 in = 0.0254m into equation(iv)</em>

=> 14.7 lb / in² = 14.7 x 453.5g / (0.0254m x 0.0254m)

=> 14.7 lb / in² = 6666.45 g / (0.00064516m²)

=> 14.7 lb / in² = 10333018.166 g / m²

<em>Therefore, 14.7 lb / in² = 10333018.166 g / m²</em>

5 0
3 years ago
Why is it important that we learn about our solar system, the sun, and planets in our solar system other than Earth?
tangare [24]

Answer:

To understand all the different kind of elements and how they work. Nature is a beautiful thing and it is important we understand how they survive and how we can help. The solar system is a mandatory nature. Learning about other planets also helps us feel safe and more knowledgable.

8 0
3 years ago
Tom kicks a soccer ball on a flat, level field with initial speed 20 m/s at an angle 35 degrees above the horizontal. (1) How lo
Arada [10]

Explanation:

Given:

x₀ = 0 m

y₀ = 0 m

v₀ = 20 m/s

θ = 35°

aᵧ = -9.8 m/s²

1) Find t when y = 0.

y = y₀ + v₀ᵧ t + ½ aᵧ t²

0 = 0 + (20 sin 35°) t + ½ (-9.8) t²

0 = t (20 sin 35° - 4.9 t)

t = 0, t = 2.34

The ball stays in the air 2.34 seconds.

2) Find y when vᵧ = 0.

vᵧ² = v₀ᵧ² + 2aᵧ (y - y₀)

0² = (20 sin 35)² + 2(-9.8) (y - 0)

y = 6.71 m

The ball reaches a maximum height of 6.71 meters.

3) Find x when y = 0.

x = x₀ + v₀ₓ t + ½ aₓ t²

x = 0 + (20 cos 35°) (2.34) + ½ (0) (2.3)²

x = 38.4 m

The ball lands 38.4 meters from Tom.

4) Find v when y = 0.

vₓ = aₓ t + v₀ₓ

vₓ = (0) (2.34) + 20 cos 35°

vₓ = 16.4 m/s

vᵧ = aᵧ t + v₀ᵧ

vᵧ = (-9.8) (2.34) + 20 sin 35°

vᵧ = -11.5 m/s

v = √(vₓ² + vᵧ²)

v = √((16.4)² + (-11.5)²)

v = 20 m/s

The ball has a speed of 20 m/s just before it lands.

5 0
3 years ago
An 80-kg quarterback jumps straight up in the air right before throwing a 0.43-kg football horizontally at 15 m/s . how fast wil
Mamont248 [21]
Applying conservation of momentum
Quarterback mass = 80 kg
ball mass = 0.43 kg
Initially both together but horizontal velocity of both 0
initial momentum = 0
Final momentum = 15*0.43 - 80v
initial = final (law of conservation of momentum)
6.45 = 80v
v = 0.08 m/s
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3 years ago
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