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lina2011 [118]
3 years ago
9

A car accelerates from rest (v. 0 m/s) with a constant acceleration of

Physics
1 answer:
oksano4ka [1.4K]3 years ago
4 0

Heya!!

For calculate final velocity, lets applicate formula

                                                \boxed{V=V_o+a*t}

                                                 <u>Δ   Being   Δ</u>

                                            V = Final Velocity = ?

                                         Vo = Initial velocity = 0 m/s

                                          a = Aceleration = 5 m/s²

                                                 t = Time = 12 s

⇒ Let's replace according the formula:

\boxed{V=0\ m/s +5\ m/s*12\ s}

⇒ Resolving

\boxed{V=60\ m/s}

Result:

The velocity after 10 sec is <u>60 meters per second (m/s)</u>

Good Luck!!

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What kind of front occurs when a cold air mass replaces a warm air mass?
Andreyy89

Answer:

Explained below:

Explanation:

When a cold air mass meets a warm air mass, a front is formed and if the cold air is replacing the warm air, it is known as a cold front. Cold fronts frequently cause thunderstorms or rain showers because they pressure the air in a steep upward direction at the front's edge. They are also responsible to bring the changes in atmospheric pressure and wind direction.

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4 years ago
Noah drops a rock with a density of 1.73 g/cm3 into a pond. Will the rock float or sink? Explain your answer
stealth61 [152]

Answer:

Sink

Explanation:

Water has a density of 1 g/cm³.  Since the density of the rock is greater than the density of water, the rock will sink.

4 0
3 years ago
Read 2 more answers
A 92kg astronaut and a 1200kg satellite are at rest relative to the space shuttle. The astronaut pushes on the satellite, giving
Harman [31]

Answer:

13.7m

Explanation:

Since there's no external force acting on the astronaut or the satellite, the momentum must be conserved before and after the push. Since both are at rest before, momentum is 0.

After the push

m_av_a + m_sv_s = 0

Where m_a = 92kg is the mass of the astronaut, m_s = 1200kg is the mass of the satellite, v_s = 0.14 m/s is the speed of the satellite. We can calculate the speed v_a of the astronaut:

v_a = \frac{-m_sv_s}{m_a} = \frac{-1200*0.14}{92} = -1.83 m/s

So the astronaut has a opposite direction with the satellite motion, which is further away from the shuttle. Since it takes 7.5 s for the astronaut to make contact with the shuttle, the distance would be

d = vt = 1.83 * 7.5 = 13.7 m

4 0
3 years ago
How long will it take for a car to travel 200 km if it has an average speed of 55 km/hr? ​
andreyandreev [35.5K]

Answer: Approximately 3.65 hours

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3 years ago
A bug of mass 2.2 g is sitting at the edge of a cd of radius 3.0 cm. if the cd is spinning at 280 rpm, what is the angular momen
m_a_m_a [10]
M = 2.2 g = 2.2 x 10⁻³ kg, the mass of the bug.
r = 3.0 cm = 0.03 m, the radial distance from the center.

The angular speed is
ω = 280 rpm
    = (280 rev/min)*(2π rad/rev)*(1/60 min/s)
    = 29.3215 rad/s

The moment of inertia of the bug is
I = mr²
  = (2.2 x 10⁻³ kg)*(0.03 m)²
  = 1.98 x 10⁻⁶ kg-m²

Calculate the angular momentum of the bug.
J = Iω
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Answer: 5.806 x 10⁻⁵ (kg-m²)/s

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4 years ago
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