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Stells [14]
3 years ago
13

After fertilization, female cones become very: sticky light O hard

Chemistry
1 answer:
S_A_V [24]3 years ago
8 0

Answer:

light

Explanation:

sorry don't now this one

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A water bottle has a mass of 14.0g. Given a density of 1.38g/cm^3, what is the volume of the plastic used to make the water bott
Kipish [7]

Answer:

\boxed{\sf Volume \ of \ plastic \ used = 10.14 \ cm^3}

Given:

Mass = 14.0 g

Density (\rho) = 1.38 g/cm³

To Find:

Volume (V)of the plastic used to make water bottle

Explanation:

Formula:

\boxed{ \bold{Density \ (\rho) = \frac{Mass \ (m)}{Volume \ (V)}}}

Substituting value of m & density in the formula:

\sf \implies 1.38 =  \frac{14.0}{V} \\  \\   \sf \implies V =  \frac{14.0}{1.38} \\  \\   \sf \implies V = 10.14 \ cm^3

\therefore

Volume of the plastic used to make water bottle = 10.14 cm³

6 0
3 years ago
PLZ HELP :) chemistry
alisha [4.7K]
Ionic bonds are formed due to tendency of a metal to donate an electron and tendency of non metal to gain an electron.
5 0
3 years ago
Indicate the number corresponding to each coefficient required to write the balanced equation for the reaction:
dimaraw [331]
The number  of corresponding to each coefficient  required to write the balanced  equation for the  reaction is as below


2 HNO3  + Mg(OH)2  =  2H2O  + Mg(NO3)2
the  coefficient  is therefore
a=2
b=1
c=2
d=1

2 moles of HNO3  reacted  with 1  mole of Mg(OH)2   to form 2 moles of H2O  and 1 mole of Mg(NO3)2
5 0
3 years ago
Read 2 more answers
Why isn’t K+ H2O —> KOH + H2 not balanced?
alex41 [277]

Answer:

The obtained result indicates that the hydrogen atom is not equal on both sides. Thus the reaction is not balanced.

Explanation:

6 0
2 years ago
The rate constant for the reaction is 0.660 M − 1 ⋅ s − 1 0.660 M−1⋅s−1 at 200 ∘ C. 200 ∘C. A ⟶ products A⟶products If the initi
Irina-Kira [14]

<u>Answer:</u> The concentration of A after 865 seconds is 0.00125 M

<u>Explanation:</u>

The integrated rate law equation for second order reaction follows:

k=\frac{1}{t}\left (\frac{1}{[A]}-\frac{1}{[A]_o}\right)

where,

k = rate constant = 0.660M^{-1}s^{-1}

t = time taken = 865 second

[A] = concentration of substance after time 't' = ?

[A]_o = Initial concentration = 0.00440 M

Putting values in above equation, we get:

0.660=\frac{1}{865}\left (\frac{1}{[A]}-\frac{1}{(0.00440)}\right)

[A]=0.00125M

Hence, the concentration of A after 865 seconds is 0.00125 M

5 0
3 years ago
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