3 years ago

How do you find the percent composition of CuBr2

Chemistry

1 answer:

Levart [38]3 years ago

7 0

Answer:

Explanation: the molar mass of the whole compound is 223.35u

now make ratios for each of the elements and multiply by 100%

copper= 63.55/223.35 x 100 % comp of copper is 28.45%

bromine= (79.9x2)/223.35 x 100 %comp of bromine is 71.54%

multiply bromines molar mass by 2 when calculating

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What is the appropriate chemical formula for Iron(III) Sulfate? Sulfate is SO_4^2 Fe3SO4 O a . Fe2(SO4)3 O b. O c. Fe2SO4 O d. F

AnnyKZ [126]

<u>Answer:</u> The chemical formula of Iron (III) sulfate is $Fe_2(SO_4)_3$

<u>Explanation:</u>

Iron is the 26th element of periodic table having electronic configuration of $[Ar]3d^64s^2$ .

To form $Fe^{3+}$ ion, this element will loose 3 electrons.

Sulfate ion is a polyatomic ion having chemical formula of $SO_4^{2-}$

By criss-cross method, the oxidation state of the ions gets exchanged and they form the subscripts of the other ions. This results in the formation of a neutral compound.

So, the chemical formula for Iron (III) sulfate is $Fe_2(SO_4)_3$

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