How do you find the percent composition of CuBr2
1 answer:
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Hope this helps you.
According to Graham's Law of Diffusion," Diffusion of Gas is inversely proportional to square root of its Molecular Mass or Density".
rᵇ/rᵃ =
Or,
rᵇ/rᵃ =
----- (1)
As,
Ma = 275 g/mol
Mb = 205 g/mol
Putting Values in eq.1,
rᵇ/rᵃ =
rᵇ/rᵃ = 1.15
Result:
Perfume B will diffuse 1.15 times faster than Perfume A. Hence, Perfume B will be first smelled by the person.
rᵇ/rᵃ =
Or,
rᵇ/rᵃ =
As,
Ma = 275 g/mol
Mb = 205 g/mol
Putting Values in eq.1,
rᵇ/rᵃ =
rᵇ/rᵃ = 1.15
Result:
Perfume B will diffuse 1.15 times faster than Perfume A. Hence, Perfume B will be first smelled by the person.