All categories

3 years ago

How do you find the percent composition of CuBr2

Chemistry

1 answer:

Levart [38]3 years ago

7 0

Answer:

Explanation: the molar mass of the whole compound is 223.35u

now make ratios for each of the elements and multiply by 100%

copper= 63.55/223.35 x 100 % comp of copper is 28.45%

bromine= (79.9x2)/223.35 x 100 %comp of bromine is 71.54%

multiply bromines molar mass by 2 when calculating

You might be interested in

Elements in the same column of the periodic table share:

avanturin [10]

B. the same number of protons.

7 0

3 years ago

Ill make u scream without the e :)<br><br><br><br> get out of my lawn

Vesnalui [34]

Answer:

Yep, this is my new pick up line

Explanation:

5 0

2 years ago

At a wastewater treatment plant, FeCl3(s) is added to remove excess phosphate from the effluent. Assume the following reactions

RoseWind [281]

Answer : The concentration of $Fe^{3+}$ needed is, $2.37\times 10^4M$

Explanation :

First we have to calculate the mole of phosphate.

As we are given that, 1 mg P/L that means, 1 mg of phosphate present in 1 L of solution.

$\text{Moles of phosphate}=\frac{\text{Mass of phosphate}}{\text{Molar mass of phosphate}}$

Molar mass of phosphate = 94.97 g/mole

$\text{Moles of phosphate}=\frac{1mg}{94.97g/mol}=\frac{0.001g}{94.97g/mol}=1.053\times 10^{-5}mol$

Now we have to calculate the concentration of phosphate.

$\text{Concentration of phosphate}=\frac{\text{Moles of phosphate}}{\text{Volume of solution}}$

$\text{Concentration of phosphate}=\frac{1.053\times 10^{-5}mol}{1L}=1.053\times 10^{-5}mol/L$

Now we have to calculate the concentration of $Fe^{3+}$ .

The second equilibrium reaction is,

$FePO_4\rightleftharpoons Fe^{3+}+PO_4^{3-}$

The solubility constant expression for this reaction is:

$K_{sp}=[Fe^{3+}][PO_4^{3-}]$

Given: $K_{sp}=\frac{1}{4}$

$\frac{1}{4}=[Fe^{3+}]\times 1.053\times 10^{-5}mol/L$

$[Fe^{3+}]=2.37\times 10^4M$

Thus, the concentration of $Fe^{3+}$ needed is, $2.37\times 10^4M$

8 0

4 years ago

In h-atom if x is radius of first bohrs orbit de broglie wavelength of an atom in 3rd orbit is a.3πx b.6πx c.9x/2 d.x/2

Step2247 [10]

Answer:

can you type question properly.

5 0

3 years ago

6. How many hydrogen ions would need to be added to the phosphate ion

steposvetlana [31]

Answer:

3 hydrogen ions

Explanation:

phosphate ion is (PO4)^-3. It has charge -3.

Hydrogen ion has charge +1.

So, we need 3 hydrogen ions,

3H^(+1) + PO4(-3) ---> H3PO4

4 0

4 years ago