Question

Y+9÷2=y-3÷4-(y/3)pls help​

Answer 1

Step-by-step explanation:

There are 2 scenarios below. One without parenthesis and the second with. I believe the second one is your question.

• y+9÷2=y-3÷4-(y/3)
• y - y + y/3 = - 3/4 - 9/2               ⇒ combining like terms
• y/3 = -3/4 - 18/4
• y/3 = -21/4
• y = -21/4*3
• y = -63/4
• y = - 15 3/4

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• (y+9)÷2=(y-3)÷4-(y/3)
• 12*(y+9)/2 = 12* (y-3)/4 - 12*y/3      ⇒ this is to get rid of fraction
• 6(y+9) = 3(y-3) - 4y
• 6y + 54 = 3y - 9 - 4y
• 6y + 54 = - y - 9
• 6y + y = - 9 - 54
• 7y = - 63
• 7y/7 = -63/7
• y = -9

Answer 2

Answer:

y = - $\frac{63}{4}$ or - 15.75

Step-by-step explanation:

Order of operations.

y + $\frac{9}{2}$ = y - $\frac{3}{4}$ - $\frac{y}{3}$ Subtract y from each side.

y - y + $\frac{9}{2}$ = y - y - $\frac{3}{4}$ - $\frac{y}{3}$

$\frac{9}{2}$ =  - $\frac{3}{4}$ - $\frac{y}{3}$   Add $\frac{3}{4}$ to each side

$\frac{9}{2}$ + $\frac{3}{4}$ = - $\frac{3}{4}$ + $\frac{3}{4}$ - $\frac{y}{3}$

$\frac{9}{2}$ + $\frac{3}{4}$ = - $\frac{y}{3}$    Find the common denominator for $\frac{9}{2}$ and $\frac{3}{4}$, which is 4

$\frac{9}{2}$ * $\frac{2}{2}$ + $\frac{3}{4}$ = - $\frac{y}{3}$

$\frac{18}{4}$ + $\frac{3}{4}$ = - $\frac{y}{3}$

$\frac{21}{4}$ = - $\frac{y}{3}$   Multiply each side by 3

$\frac{21}{4}$  * 3 = - $\frac{y}{3}$ * 3

$\frac{63}{4}$ = - y      Divide each side by -1

y = - $\frac{63}{4}$ = - 15 $\frac{3}{4}$

y = - 15.75