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3 years ago

What net force acting on a 14 KG wagon produces an acceleration of 1.5 MS^2?

Physics

1 answer:

valentina_108 [34]3 years ago

7 0

21N

Explanation:

Given parameters:

Mass of wagon = 14kg

Acceleration = 1.5m/s²

Unknown:

Net force on wagon = ?

Solution:

Force is a pull or push on a body that causes a body to change its state. It is expressed as:

Force = mass x acceleration

Force on wagon = 14 x 1.5 = 21N

Learn more:

Force brainly.com/question/10470406

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Collapse question part Part 4 (d) What is the unit vector in the direction of the spacecraft's velocity? (Express your answer in

Maksim231197 [3]

Answer:

unit (v) = [ -0.199 i - 0.8955 j + 0.39801 k ]

Explanation:

Given:

v = (-23.2, -104.4, 46.4) m/s

Above expression describes spacecraft's velocity vector v.

Find:

Find unit vector in the direction of spacecraft velocity v.

Solution:

Step 1: Compute magnitude of velocity vector.

mag (v) = sqrt ( 23.2^2 + 104.4^2 + 46.4^2)

mag (v) = 116.58 m/s

Step 2: Compute unit vector unit (v)

unit (v) = vec (v) / mag (v)

unit (v) = [ -23.2 i -104.4 j + 46.4 k ] / 116.58

unit (v) = [ -0.199 i - 0.8955 j + 0.39801 k ]

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3 years ago

The area around a charged object that can exert a force on other charged objects is an electric ___

Ymorist [56]

Answer is:

Electric field.

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3 years ago

The atomic number of beryllium (Be) is 4, and the atomic number of barium (Ba) is 56. Which comparison is best supported by this

svlad2 [7]

Answer: They are in the same group because they have similar chemical properties, but they are in different periods because they have very different atomic numbers.

Explanation: On Edgenuity!!

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3 years ago

You place an ice cube of mass 7.50×10−3kg and temperature 0.00∘C on top of a copper cube of mass 0.540 kg. All of the ice melts,

lbvjy [14]

Answer:

The value is $T_c = 12 .1 ^oC$

Explanation:

From the question we are told that

The mass of the ice cube is $m_i = 7.50 *10^{-3} \ kg$

The temperature of the ice cube is $T_i = 0^o C$

The mass of the copper cube is $m_c = 0.540 \ kg$

The final temperature of both substance is $T_f = 0^oC$

Generally form the law of thermal energy conservation,

The heat lost by the copper cube = heat gained by the ice cube

Generally the heat lost by the copper cube is mathematically represented as

$Q = m_c * c_c * [T_c - T_f ]$

The specific heat of copper is $c_c = 385J/kg \cdot ^oC$

Generally the heat gained by the ice cube is mathematically represented as

$Q_1 = m_i * L$

Here L is the latent heat of fusion of the ice with value $L = 3.34 * 10^{5} J/kg$

$Q_1 = 7.50 *10^{-3} * 3.34 * 10^{5}$

=> $Q_1 = 2505 \ J$

$2505 = 0.540 * 385 * [T_c - 0 ]$

=> $T_c = 12 .1 ^oC$

4 0

3 years ago

A rock is thrown horizontally from a bridge with a speed of 29.0 m/s. if the rock is 23.7 meters above the river at the moment o

mash [69]

It would be 1.5 meters im sure form that distance to me is that nswe

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3 years ago