Answer:
hello your question is incomplete attached below is the complete question
answer : The moment of inertial felt by someone ( J ) is greater that the moment of inertia felt by the motor i.e. J > Jm
Explanation:
Gear ratio G > 1
a) Determine the moment of inertia felt by the motor
moment of inertia felt by Motor = moment of Inertia at the armature
b) Determine the moment of inertial felt by someone who is rotating the mass by hand
moment of inertia felt by someone is = J
The moment of inertial felt by someone ( J ) is greater that the moment of inertia felt by the motor
attached below is a detailed solution
Answer:
36 N
Explanation:
If the object of mass, m = 8 kg is swung in a horizontal circle of radius, r = 2m = length of string with tangential velocity v = 3 m/s, the tension in the string is the centripetal force which is T = mv²/r
= 8 kg × (3 m/s)²/2 m
= 4 kg × 9 m/s²
= 36 N
Answer:it should be Newton’s second law
Explanation: lmk if I’m wrong
Using lens equation;
1/o + 1/i = 1/f; where o = Object distance, i = image distance (normally negative), f = focal length (normally negative)
Substituting;
1/o + 1/-30 = 1/-43 => 1/o = -1/43 + 1/30 = 0.01 => o = 1/0.01 = 99.23 cm
Therefore, the object should be place 99.23 cm from the lens.
Answer:
<em>1,378.9ms²</em>
Explanation:
Given the following
Distance S = 70.6m
Time t = 0.32secs
Initial velocity = 0m/s
Required
Acceleration
Using the equation of motion
S = ut+1/2at²
Substitute
70.6 = 0+1/2a(0.32)²
70.6 = 0.0512a
a = 70.6/0.0512
a = 1,378.9
<em>Hence the acceleration is 1,378.9ms²</em>
