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stiv31 [10]
3 years ago
13

Calculate the electric potential energy in a capacitor that stores 4.0 x 10-10 C

Physics
2 answers:
serious [3.7K]3 years ago
5 0

5.0•10^-8J

Ape.x .........-_-

ioda3 years ago
4 0

The electric potential energy is 1\cdot 10^{-7} J

Explanation:

The electric potential energy stored in a capacitor is given by the equation

PE=Q \Delta V

where

Q is the charge stored in the capacitor

\Delta V is the potential difference between the plates

For the capacitor in this problem, we have

Q=4.0\cdot 10^{-10}C is the charge

\Delta V=250.0 V is the potential difference

Substituting, we find the potential energy:

PE=(4.0\cdot 10^{-10})(250.0)=1\cdot 10^{-7} J

Learn more about capacitors:

brainly.com/question/10427437

brainly.com/question/8892837

brainly.com/question/9617400

#LearnwithBrainly

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his speed is : FAST AS ALL GET OUT



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A bird is about 6.26.2 in.​ long, with a​ thin, dark bill and a​ wide, white wing stripe. If the bird can fly 9292 mi with the w
Trava [24]

Answer:

209 mph

Explanation:

V = Speed of bird in still air

v = Speed of wind = 44 mph

Consider the motion of the bird with the wind

D_{1} = distance traveled with the wind = 9292 mi

t_{1} = time taken to travel the distance with wind

Time taken to travel the distance with wind is given as

t_{1} = \frac{D_{1}}{V + v}

t_{1} = \frac{9292}{V + 44}                              eq-1

Consider the motion of the bird with the wind

D_{2} = distance traveled against the wind = 6060 mi

t_{2} = time taken to travel the distance against wind

Time taken to travel the distance against wind is given as

t_{2} = \frac{D_{2}}{V + v}

t_{2} = \frac{6060}{V - 44}                              eq-2

As per the question,

Time taken with the wind = Time taken against the wind

t_{1} = t_{2}

\frac{9292}{V + 44} = \frac{6060}{V - 44}

(9292) (V - 44) = (6060) (V + 44)

9292V - 408848 = 6060V + 266640

3232V = 675488

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5 0
3 years ago
A light, a heater, and a hair dryer were all running in the bathroom at the same time. Suddenly, they all turn off. After all, t
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Well depending on what current the heater pulls im going to assume about 13, and 13A for the hair dryer, thats 26A on the 40A circuit.
I dont see how a lightbulb could overload the circuit. 

Anyway, assuming the circuit is overloaded by some really big heater- the circuit would trip, the fuse would go and remain off. Most houses are fitted with seperate circuits for lights and sockets, so the light may remain on depending on the breaker board. - the reason for them all being able to run with the sudden overload may be due to a surge.

One solution to this is not to put such a large heater on the circuit with other appliances. 

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3 years ago
In the combined gas law, if the volume is decreased, what happens to the temperature if pressure remains constant?
erastovalidia [21]
A. The temperature decreases.
8 0
3 years ago
A test charge is placed at a distance of 3.5 meters from a charge of 8.7 × 10-9 coulombs. What is the electric field strength at
zavuch27 [327]
In order to calculate the electric field strength, we may use the formula:
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