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3 years ago

13

Calculate the electric potential energy in a capacitor that stores 4.0 x 10-10 C

2 answers:

serious [3.7K]3 years ago

5 0

5.0•10^-8J

Ape.x .........-_-

ioda3 years ago

4 0

The electric potential energy is $1\cdot 10^{-7} J$

Explanation:

The electric potential energy stored in a capacitor is given by the equation

$PE=Q \Delta V$

where

Q is the charge stored in the capacitor

$\Delta V$ is the potential difference between the plates

For the capacitor in this problem, we have

$Q=4.0\cdot 10^{-10}C$ is the charge

$\Delta V=250.0 V$ is the potential difference

Substituting, we find the potential energy:

$PE=(4.0\cdot 10^{-10})(250.0)=1\cdot 10^{-7} J$

Learn more about capacitors:

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When hydrogen is heated or subjected to an electric discharge, it emits light with specific visible wavelengths. A diffraction g

BartSMP [9]

To solve this problem we will apply the concepts related to the double slit-experiment. For which we will relate the distance between the Slits and the Diffraction Angle with the order of the bright fringe and the wavelength, this is mathematically given as,

$d sin\theta = m\lambda$

Here,

d = Distance between Slits

m = Order of the fringes

$\lambda$ = Wavelength

$\text{Spacing between adjacent lines}$ = $d = 4926nm$

$\text{Wavelength of light} = \lambda = 656nm$

Rearranging to find the angle,

$sin\theta = \frac{m\lambda}{d}$

$\theta = sin^{-1}(\frac{m\lambda}{d})$

$\theta = sin^{-1}(\frac{(4)(656*10^{-9}m)}{4926*10^{-9}m})$

$\theta = 32.19\°$

Therefore the angle that the fourth order bright fringe occur for this specific wavelenth of light occur is 32.19°

3 0

3 years ago

Electrical wire with a diameter of .5 cm is wound on a spool with a radius of 30 cm and a height of 24 cm.

kow [346]

Answer:

a) # lap = 301.59 rad , b) L = 90.48 m

Explanation:

a) Let's use a direct proportions rule (rule of three). If one turn of the wire covers 0.05 cm, how many turns do you need to cover 24 cm

# turns = 1 turn (24 cm / 0.5 cm)

# laps = 48 laps

Let's reduce to radians

# laps = 48 laps (2 round / 1 round)

# lap = 301.59 rad

b) Each lap gives a length equal to the length of the circle

L₀ = 2π R

L = # turns L₀

L = # turns 2π R

L = 48 2π 30

L = 9047.79 cm

L = 90.48 m

6 0

3 years ago

Your friends sit in a sled in the snow. If you apply a force pf 75 N to them, they have an acceleration of 0.9 m/s ^ 2. What is

Elza [17]

Answer:

Mass of the sled in the snow 83.33 kg.

<u>Explanation</u>:

Given that,

Force applied to move the sled in the snow (F) = 75N

$\text { Acceleration }(a)=0.9 \mathrm{m} / \mathrm{s}^{2}$

We know that

Newton's second law of motion is

$\text { Force }=\text { mass } \times \text { acceleration }$

F = ma (Or "force" is equal to "mass" times "acceleration".)

So if we move this around we can isolate mass and get mass

$\text { Mass }=\frac{\text { force }}{\text { accelearation }}$

$\mathrm{M}=\frac{75}{0.9}$

M = 83.33 kg

Mass of the sled in the snow <u>83.33 kg.</u>

3 0

3 years ago

Which value is equivalent to 7.2 kilograms?

Elis [28]

B is the right answer glad I could help !!

3 0

3 years ago

A car on a freeway speeds up to get around another car. The car speeds up from 20 m/s to 35 m/s in 5 seconds.

Tanzania [10]

Answer:

Initial speed = 20 m/s

Final speed = 35 m/s

Time to speed up = 5 seconds

Explanation:

Directly from the information given:

Initial speed = 20 m/s

Final speed = 35 m/s

Time to speed up = 5 seconds

5 0

3 years ago