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stiv31 [10]
3 years ago
13

Calculate the electric potential energy in a capacitor that stores 4.0 x 10-10 C

Physics
2 answers:
serious [3.7K]3 years ago
5 0

5.0•10^-8J

Ape.x .........-_-

ioda3 years ago
4 0

The electric potential energy is 1\cdot 10^{-7} J

Explanation:

The electric potential energy stored in a capacitor is given by the equation

PE=Q \Delta V

where

Q is the charge stored in the capacitor

\Delta V is the potential difference between the plates

For the capacitor in this problem, we have

Q=4.0\cdot 10^{-10}C is the charge

\Delta V=250.0 V is the potential difference

Substituting, we find the potential energy:

PE=(4.0\cdot 10^{-10})(250.0)=1\cdot 10^{-7} J

Learn more about capacitors:

brainly.com/question/10427437

brainly.com/question/8892837

brainly.com/question/9617400

#LearnwithBrainly

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3 In a television tube, an electron starting from rest experiences a force of 4.0 × 10−15 N over a distance of 50 cm. The final
MAXImum [283]

Answer:

The final speed of the electron = 2.095×10⁸ m/s

Explanation:

From newton's fundamental equation of dynamics,

F = ma ........................Equation 1

Where F = force, m = mass of the electron, a = acceleration of the electron.

making a the subject of the equation,

a = F/m.................... Equation 2

Given: F = 4.0×10⁻¹⁵ N,

Constant: m =  9.109×10⁻³¹ kg.

Substituting into equation 2

a = 4.0×10⁻¹⁵/9.109×10⁻³¹

a = 4.39×10¹⁶ m/s².

Using newton's equation of motion,

v² = u²+2as .......................... Equation 3

Where v = final velocity of the electron, u = initial velocity of the electron, a = acceleration of the electron, s = distance covered by the electron.

Given: u = 0 m/s(at rest), s = 50 cm = 0.5 m, a = 4.39×10¹⁶ m/s²

Substituting into equation 3

v² = 0² + 2(0.5)(4.39×10¹⁶)

v = √(4.39×10¹⁶)

v = 2.095×10⁸ m/s

Thus the final speed of the electron = 2.095×10⁸ m/s

7 0
3 years ago
Which of the following has to happen for Earth's shadow to fall on the moon?
Ronch [10]
The correct answer is a, lunar eclipse
6 0
2 years ago
Can someone help me with this question
Mademuasel [1]

Answer:

Net force: 20 N to the right

mass of the bag: 20.489 kg

acceleration:  0.976  m/s^2

Explanation:

Since the normal force and the weight are equal in magnitude but opposite in direction, they add up to zero in the vertical direction. In the horizontal direction, the 195 N tension to the right minus the 175 force of friction to the left render a net force towards the right of magnitude:

195 N - 175 N = 20 N

So net force on the bag is 20 N to the right.

The mass of the bag can be found using the value of the weight force: 201 N:

mass = Weight/g = 201 / 9.81 = 20.489 kg

and the acceleration of the bag can be found as the net force divided by the mass we just found:

acceleration = 20 N / 20.489 kg = 0.976  m/s^2

8 0
3 years ago
How does upwelling affect the weather of a coastal region?
SIZIF [17.4K]

c.The warm surface water results in moist air and more rainfall.

Explanation:

  • During upwelling, cold water in the ocean is stirred up and brought to the surface.
  • The warmer surface water is then taken into deeper parts of the ocean.
  • Upwelling allows for nutrient mixing in the ocean and allows for useful gases to circulate well.
  • The warm surface water causes the air to be moisty.
  • When the air is carried landward towards the coast, it leads to rainfall when the saturated air releases the water.
  • The air then becomes cold and dry and it rises up.
  • Therefore, warm surface water results in moist air and more rainfall.

Learn more:

Ocean current brainly.com/question/4117397

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4 0
3 years ago
Read 2 more answers
Paco pulls a 67 kg crate with 738 N and of force across a frictionless floor 9.0 M how much work does he do in moving the crate
olga_2 [115]

Answer:

W = 6642 J

Explanation:

Given that,

Mass of a crate, m = 67 kg

Force with which the crate is pulled, F = 738 N

It is moved 9 m across a frictionless floor

We need to find the work done in moving the crate. Let the work done is W. It is given by :

W = F d

W = 738 N × 9 m

= 6642 J

So, the work done is 6642 J.

5 0
2 years ago
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